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There are two possible sums that add up to a number evenly divisible by 2 and 3, namely 6 and 12.

There are 5 different ways to roll a sum of 6, so the probability of that happening is 5/36.

There is 1 way to roll a sum of 12, so the probability of that happening is 1/36.

The probability of either happening is the sum of the two separate probabilities.

p=5/36+1/36=6/36=1/6 ~= .1667 = 16.67%

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Q: An experiment consists of rolling two fair dice and adding the dots on the two sides facing up therefore what is the probability that the sum of the dots is divisible by 2 and 3?
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