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When dealing with sets that have mutually disjointed (distinct) elements, IE they are under the system defined by Kolmogorov axioms, they cannot be negative. These are the probabilities normally dealt with.

However, when you deal with issues in quantum mechanics etc, where each element is not distinct, then negative probabilities arise and are used as an intermediary step.The end result will not contain a negative probability when dealing with such quasiprobability systems.

Q: Can a probability be negative

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no, z score can be negative but a probability is a always positive between 0 and 1.

No, it can't.

The outcomes of a trial can be a negative integer but the probability of any outcome must be in the range [0, 1].

No; because probability can never be less than zero.

It depend how many negative numbers are written on the cube.

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No. The probability cannot be negative.

No. Probability values always have to be positive.

no, z score can be negative but a probability is a always positive between 0 and 1.

No, it can't.

no

Probability is a ratio of two counts: both of which MUST be positive. Their ratio cannot be negative.

Yes it can be negative.

The outcomes of a trial can be a negative integer but the probability of any outcome must be in the range [0, 1].

Yes it can. E.g there may be a probability it may rain tomorrow. See, negative. Negative probability is like an opinion of your own except probabilities aren't opinions, anyway you get what I mean.

No; because probability can never be less than zero.

No. Probability is always represented as a positive ratio/fraction/percent.

If a p-value is negative then there is something very seriously wrong - either with the probability model or your calculations.If a p-value is negative then there is something very seriously wrong - either with the probability model or your calculations.If a p-value is negative then there is something very seriously wrong - either with the probability model or your calculations.If a p-value is negative then there is something very seriously wrong - either with the probability model or your calculations.