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Yes.

However, a z-score greater than 3 implies either that the outcome is rare (prob = 0.135%) or that some of the assumptions regarding the variable are incorrect. This could be the distribution itself or its parameters.

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11y ago

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What does a positive Z-score mean?

it means that the score is above the mean


In a standard normal distribution about percent of the scores fall above a z score of 300?

A Z score of 300 is an extremely large number as the z scores very rarely fall above 4 or below -4. About 0 percent of the scores fall above a z score of 300.


If a very bright student is described as having an IQ that is three stand deviations above the mean what would the z-score be?

z = 3


What is the area above a z-score of 1.28?

It is 0.1003


What is the difference between z-score and t-score?

T-scores and z-scores measure the deviation from normal. The normal for T-score is 50 with standard deviation of 10. if the score on t-score is more than 50, it means that the person scored above normal (average), and vise versa. The normal for Z-score is 0. If Z-score is above 0, then it means that person scored above normal (average), and vise versa.


What proportion of a normal distribution falls above a z-score of 1.16?

Pr(Z > 1.16) = 0.123


Which z score corresponds to a higher value within a distribution of values -1.4 or 1.00?

A z-score indicates how many standard deviations a value is from the mean of a distribution. A z-score of 1.00 is positive, meaning it is above the mean, while a z-score of -1.4 is negative, indicating it is below the mean. Therefore, a z-score of 1.00 corresponds to a higher value within the distribution compared to a z-score of -1.4.


What is the z score if 30 percent of the curve lies to the left of the z?

The z-score is 0.84. In the related link, look in the body of the table for .3 area (.2995 closest) and it yields the .84 z-score.


What proportion of a normal distribution falls above a z-score of 2.10?

It is 0.017864


How many students of 1800 will have an IQ score above 109 with a mean of 100 and a standard deviation of 15?

You can find this using a table of z scores.Z = (x - mu) / sZ = (109 - 100) /15 = 9/15 = 3/5 = .6You want the percentage of students having a z score above .6.p = 1 - .7257 = .2743.2743 * 1800 = 493 students with a score above 109


A z-score of plus 1.6 represents?

It is 1.6 standard deviations above the mean.


How do you calculate a raw score from a z score?

z = (x - μ) / σ is the formula where x is the raw score and z is the z-score. μ and σ are the mean and standard deviations and must be known numbers. Multiply both sides by σ zσ = x-μ Add μ to both sides μ + zσ = x x = μ + zσ You calculate the raw score x , given the z-score, μ and σ by using the above formula.

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