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z = (x - μ) / σ is the formula where x is the raw score and z is the z-score. μ and σ are the mean and standard deviations and must be known numbers.
Multiply both sides by σ
zσ = x-μ
Add μ to both sides
μ + zσ = x
x = μ + zσ
You calculate the raw score x , given the z-score, μ and σ by using the above formula.
What else can I help you with?
What is the z score for a given raw score?
Let your raw score be x and M the mean and S the standard deviation. The Z score for your specific x is Z=(x-M)/S So say your score is 80 (out of 100) and the mean is 70 and the standard deviation is 10. Then the z score for your 80 is: (80-70)/10=1 If on the other hand you got a 60, then the z score would be -1.
What is the z score for 0.71?
This question cannot be answered. You need the mean and standard deviation in order to compute a Z score for a Raw score. Please restate the question.
What z-score corresponds to this value?
There is insufficient information in the question to answer it. To determine Z score, you need raw score, mean, and standard deviation. Please restate the question.
How do you calculate standard deviation with the help of z-score?
A z-score cannot help calculate standard deviation. In fact the very point of z-scores is to remove any contribution from the mean or standard deviation.
What is the z score of x equals 108?
You need the mean and standard deviation in order to calculate the z-score. Neither are given.
How do you calculate raw score if z-score is given?
Without more information you cannot.
How do you compute a z-score for the Beery VMI?
To compute a z-score for the Beery Visual-Motor Integration (VMI) test, first obtain the raw score from the test. Then, use the mean and standard deviation of the normative sample for the Beery VMI to calculate the z-score using the formula: ( z = \frac{(X - \mu)}{\sigma} ), where ( X ) is the raw score, ( \mu ) is the mean, and ( \sigma ) is the standard deviation. The resulting z-score indicates how many standard deviations the raw score is from the mean of the normative population.
What does it mean if the Z score of a test is equal to 0?
If the Z Score of a test is equal to zero then the raw score of the test is equal to the mean. Z Score = (Raw Score - Mean Score) / Standard Deviation
Is a negative z score always an indicator that the raw score is below the mean?
Yes.z = (raw score - mean)/standard error.Since the standard error is positive, z < 0 => (raw score - mean) < 0 => raw score < mean.
Does a positive raw score always result in a positive z score?
No.
Calculate the z-score for a test score of 87 if the mean test score is 81.1 and standrd deviation is 11.06?
z score = (test score - mean score)/SD z score = (87-81.1)/11.06z score = 5.9/11.06z score = .533You can use a z-score chart to calculate the probability from there.
What is the z score for a raw score of 70?
There is not enough information to answer your question. To determine a Z-Score, the mean and standard deviation are also required.
What is the z score for a given raw score?
Let your raw score be x and M the mean and S the standard deviation. The Z score for your specific x is Z=(x-M)/S So say your score is 80 (out of 100) and the mean is 70 and the standard deviation is 10. Then the z score for your 80 is: (80-70)/10=1 If on the other hand you got a 60, then the z score would be -1.
What the z-score of a person with a raw score of 20?
There is not enough information to answer your question. To determine a Z-Score, the mean and standard deviation is also required.
A raw score of 6 has a z score of what?
A z-score requires the mean and standard deviation (or standard error). There is, therefore, not enough information to answer the question.
What is the z score for 0.71?
This question cannot be answered. You need the mean and standard deviation in order to compute a Z score for a Raw score. Please restate the question.
What z-score corresponds to this value?
There is insufficient information in the question to answer it. To determine Z score, you need raw score, mean, and standard deviation. Please restate the question.
