orgy
It is 0.6050
59
25.1%The probability of having at least two same number balls when 7 balls are drawn withreplacement from a box containing 75 numbered balls from 1 to 75 is calculated asfollows:We calculate the probability of drawing 7 times a ball (with replacement) and havingall different numbers. Then we subtract this value from 1. This will be the probabilityof all the possibilities of combinations of 7 numbers where at least two are repeated.1.- For the 1st ball the options are 75/75.2.- For the 2nd ball the options for not repeating the 1st number are 74/75.3.- For the 3rd ball the options for not repeating the previous two numbers are 73/75.4.- For the 4th ball the options for not repeating the previous three numbers 72/75.5.- For the 5th ball ........................................................................... 71/75.6.- For the 6th ball ........................................................................... 70/75.7.- For the 7th ball ........................................................................... 69/75.The probability of drawing seven balls (with replacement) having all different numbersis: 75/75(74/75)(73/75)(72/75)(71/75)(70/75)(69/75) = 0.749419476...The probability of having at least two same number balls when 7 balls are drawn with replacement from the given box is:P = 1 - 0.749419476... = 0.250580524...≈ 25.1%
Let's consider first one bag: The probability to grab one green marble is Pg=1/5 The probability to grab one red marble is Pr=1-Pg=4/5 For the 4 bags, it's a binomial distribution: probability to get k green out of n bags, P(X=k)=nCk pk (1-p)n-k = nCk Pgk Prn-k Now, the probability to grab at least 2 green marbles from 4 bags is 1 - (Probability to get no green marble from 4 bags) - (Probability to get just one green marble from 4 bags) Probability to get no green marble is = 4C0 (4/5)4 = (4/5)4 (n=4, k=0, no green marble from each bag, 4C0 Pr4) Probability to get just one green marble is = 4C1 (1/5) (4/5)3 (n=4, k=1, one green marble from one bag and red marbles from the other ones, 4C1 Pg Pr3) Probability to grab at least 2 green marbles from 4 bags is 1-(4/5)4-4*(1/5)(4/5)3 = 0.1801
The probability that three F2 seeds chosen from Mendel's study group will have at least one yellow seed is 63/64. It would be very rare to get three green seeds.
ans : 3720
7
8
For every tennis match there maybe 60 balls needed
balls
Nitro
The pigeonhole principle is merely the following observation - "If we are to place N balls into M boxes where N > M, at least one box will contain at least two balls." A generalized version of the pigeonhole principle says that if we place at least nk + 1 balls into n boxes, then at least one box will contain at least k+1 balls. I say "at least" a lot because these numbers are arbitrary and lower bounds.
Popcorn balls
Alumina ball is a kind of ceramic balls. Here are at least four kinds ceramic balls as I know--Silicon Nitride balls, Silicon Carbide balls, Zirconia balls and Alumina balls.
-native basket -native fan
Have the door eat the balls in the following order: Yellow, blue, red, green. ____ The color order is according to how many times the colors appear on the wall, from least to greatest. (Yellow blue red green) Feed him from sun to leaf.
There are at least 11 green marbles in the bag.