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Let's consider first one bag:
The probability to grab one green marble is Pg=1/5
The probability to grab one red marble is Pr=1-Pg=4/5
For the 4 bags, it's a binomial distribution: probability to get k green out of n bags,
P(X=k)=nCk pk (1-p)n-k = nCk Pgk Prn-k
Now, the probability to grab at least 2 green marbles from 4 bags is
1 - (Probability to get no green marble from 4 bags) - (Probability to get just one green marble from 4 bags)
Probability to get no green marble is = 4C0 (4/5)4 = (4/5)4
(n=4, k=0, no green marble from each bag, 4C0 Pr4)
Probability to get just one green marble is = 4C1 (1/5) (4/5)3
(n=4, k=1, one green marble from one bag and red marbles from the other ones, 4C1 Pg Pr3)
Probability to grab at least 2 green marbles from 4 bags is
1-(4/5)4-4*(1/5)(4/5)3 = 0.1801
What else can I help you with?
What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?
The probability of drawing a white marble is .46
A marble is selected from a random jar containing 3 red marbles 4 yellow marbles and 2 marbles what are the odds in favor of selecting a red marble?
The probability of selecting a red marble is 3/9
What is the probability of choosing a green marble from A jar containing 4 red 7 green and 5 blue marbles?
There are 16 marbles total and 7 green ones, so the probability is 7/16.
What is the probability of choosing a green marble from A jar containing 4 red 6 green and 5 blue marbles?
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
What is the probability of picking a red marble and then a blue marble?
None, if all the marbles that you have are yellow!
What are the odds in favor of choosing a white marble from a bag containing 3 black marbles 4 green marbles and 6 white marbles?
The probability of drawing a white marble is .46
A marble is selected from a random jar containing 3 red marbles 4 yellow marbles and 2 marbles what are the odds in favor of selecting a red marble?
The probability of selecting a red marble is 3/9
What is the probability of choosing a marble that is not blue in problem 2?
if there is a jar containing 5 red marbles 6green and 4 blue what is the probability off not chossing a blue marble
What is the probability of choosing a green marble from A jar containing 4 red 7 green and 5 blue marbles?
There are 16 marbles total and 7 green ones, so the probability is 7/16.
Is the probability that a blue marble will NOT be selected from a bag containing 9 red marbles 6 blue marbles 7 green marbles and 11 yellow marbles if one is selected randomly?
To find the probability that a blue marble will NOT be selected, first calculate the total number of marbles: 9 red + 6 blue + 7 green + 11 yellow = 33 marbles. The number of non-blue marbles is 9 red + 7 green + 11 yellow = 27 marbles. Therefore, the probability of NOT selecting a blue marble is 27/33, which simplifies to 9/11.
If you have a bag containing 24 marbles If the probability of drawing a red marble is twice as likely not drawing a red marble how many red marbles are in the bag?
Suppose probability of drawing a red marble is p. Then p = 2*(1 - p) that is p = 2 - 2p or p = 2/3 So 2/3 of the 24 marbles are red 24*(2/3) = 16 red marbles.
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
What is the probabilityof choosing a green marble from a jar containing 5 red 6 green and 4 blue marbles?
The probability of choosing a green marble from this jar would be 6/15. You get this answer by adding up the sum of all the marbles.
What is the probability of choosing a green marble from A jar containing 4 red 6 green and 5 blue marbles?
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
What is the probability of getting a green marble?
To determine the probability of getting a green marble, you need to know the total number of marbles and the number of green marbles specifically. The probability is calculated by dividing the number of green marbles by the total number of marbles. For example, if there are 5 green marbles out of 20 total marbles, the probability would be 5/20, which simplifies to 1/4 or 25%.
What is the probability of not drawing a green marble?
To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.
