Let's consider first one bag:
The probability to grab one green marble is Pg=1/5
The probability to grab one red marble is Pr=1-Pg=4/5
For the 4 bags, it's a binomial distribution: probability to get k green out of n bags,
P(X=k)=nCk pk (1-p)n-k = nCk Pgk Prn-k
Now, the probability to grab at least 2 green marbles from 4 bags is
1 - (Probability to get no green marble from 4 bags) - (Probability to get just one green marble from 4 bags)
Probability to get no green marble is = 4C0 (4/5)4 = (4/5)4
(n=4, k=0, no green marble from each bag, 4C0 Pr4)
Probability to get just one green marble is = 4C1 (1/5) (4/5)3
(n=4, k=1, one green marble from one bag and red marbles from the other ones, 4C1 Pg Pr3)
Probability to grab at least 2 green marbles from 4 bags is
1-(4/5)4-4*(1/5)(4/5)3 = 0.1801
The probability of drawing a white marble is .46
The probability of selecting a red marble is 3/9
There are 16 marbles total and 7 green ones, so the probability is 7/16.
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
The probability of drawing a white marble is .46
The probability of selecting a red marble is 3/9
if there is a jar containing 5 red marbles 6green and 4 blue what is the probability off not chossing a blue marble
There are 16 marbles total and 7 green ones, so the probability is 7/16.
Suppose probability of drawing a red marble is p. Then p = 2*(1 - p) that is p = 2 - 2p or p = 2/3 So 2/3 of the 24 marbles are red 24*(2/3) = 16 red marbles.
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
The probability of choosing a green marble from this jar would be 6/15. You get this answer by adding up the sum of all the marbles.
Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
None, if all the marbles that you have are yellow!
probability of pulling out a purple marble = 20/85probability of NOT pulling out a purple marble = 1 - 20/85 = 65/85 = 13/17