1x20 2x10 5x4
They would be 1 and 36, 2 and 18, 3 and 12, 4 and 9, and 6 and 6.
There are infinitely many possible answers.A simple one is 1 times 20.A less simple one is -4 times -5A really unusual answer is 2+4i and 2-4i where i is the imaginary square root of -1.
There are (10 x 9)/2 = 45 different possible pairs of 2 teachers. For each of these . . .There are (30 x 29)/2 = 435 different possible pairs of students.The total number of different committees that can be formed is (45 x 435) = 19,575 .
Assuming the 36 numbers are all different, there are 36*35/2 = 630 pairs.
The factor pairs of 29 are 1 and 29. 29 is prime so it has only one factor pair.
1 x 58 = 58 2 x 29 = 58 Therefore, factor pairs = 1 and 58, 2 and 29.
There are 2 factor pairs of 87:87 = 1 x 8787 = 3 x 29
The factor pairs of 58 are 58 and 1, and 29 and 2.
The factor pairs of 116 are: 116 x 1 58 x 2 29 x 4
The factor pairs of 145 are: 1 × 145 5 × 29
The factor pairs of 464 are: 1 x 464 2 x 232 4 x 116 8 x 58 16 x 29
1 x 87, 3 x 29, 29 x 3, 87 x 1
The factors of 203 are 1, 7, 29, and 203. The factor pairs of 203 are (1, 203) and (7, 29).
1, 2, 4, 8, 29, 58, 166, 232
Yes. Factor pairs are always repeated across pairs since factor pairs are certain kinds of pairs.
the factor pairs are 1x35 & 5x7