The number of combinations from 16 finalists drawn 3 at a time is16C3, which is 560. Since only 1 of the three groups of 560 contains the winners, the probability of guessing the top 3 winners is 1/560 or 0.001786.
The probability with 30 people is 0.7063 approx.
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
The particular student can be in any one of 3 groups and so the probability of being in group 2 is 1/3.
This is a Binomial Probability Distribution; n=4, p=0.6. The probability of at least 1 passed is equal to the probability of 1-none passed; so x=0. The probability of x=0 (with n=4, p=0.6) is 0.0256. So, the probability of at least 1 passed is 1-0.0256 or 0.9744.
Birth months are not uniformly distributed across the year. However, if yo assume that they are, the probability is 0.9536 (approx).
The Portuguese equivalent of the English word 'winners' is ganhadores. The Portuguese pronounciation is gah-nyah-DOH-reesh. The word can be used to refer to a group of all male winners or of all female winners; or to a mixed group of female and male winners.
an orchestral group im guessing
the larger the group, the more likely the statistical probability of loss will be equal
im guessing advertisement
There are 8 groups, A,B,C,D,E,F,G and H. The winners of group A play the runners up of group B, the winners of Group B play the runners up of group A etc See related link for full break down.
Im guessing eukatorya.
Yes, relative frequency probability uses group information and applies it to single cases.
im guessing that you're asking what group tin is in and ironically its in the Metal group
independent
2 numbers. few probabilities. Lets see. Number 1 probability: if your given numbers are this for example, 2 and 7. What is the probability of picking out 7? the Numerator is how many of that number is in the group. They are asking for 7? so how many 7's are in the group? 1. Then the denominator is how many numbers are in the group. There are 2 numbers in the group. so the probability of picking out a 7 would be 1/2. get it? if there were two 7's, then the probability would be 2/2 or 1. I hope I helped.
The probability with 30 people is 0.7063 approx.
Well... a group of frogs is called an army, so I'm guessing that your answer is: Army