2 numbers. few probabilities. Lets see. Number 1 probability: if your given numbers are this for example, 2 and 7. What is the probability of picking out 7? the Numerator is how many of that number is in the group. They are asking for 7? so how many 7's are in the group? 1. Then the denominator is how many numbers are in the group. There are 2 numbers in the group. so the probability of picking out a 7 would be 1/2. get it? if there were two 7's, then the probability would be 2/2 or 1. I hope I helped.
First you will need to pick out the two numbers. Then you can use your textbook and the instructions in order to draw out the flow chart.
you add the two numbers that r given then you subtract 180 from the number you got and their you go you will have the answer
To find the median with two numbers, do as you would to find the "average" or the "mean" by finding the sum between the two numbers and dividing the sum (or total) by two.
you find the two numbers in the middle and add them. divide the sum by two. that's the median.
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
If A and B are independent, then you can multiply the two probabilities
draw a flow chart to find hcf of two given numbers
It is not possible to answer the question without knowing anything about the set of numbers that they are pulled from.
The probability that a spinner with N sides stops on 2 particular numbers in two spins in 1 in N2. It does not matter what the two numbers are, since the two spins are sequentially unrelated.
To find a pair of numbers with a given GCF, take the GCF number and double it. The pair of numbers is the GCF, and two times the GCF. For instance, two numbers with a GCF of 3 are 3 and 6.
The probability is 0.
The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.
Add them together and divide by 2 will give one of the rational numbers between two given rational numbers.
On the basis that numbers are a continuous variable, the probability of any particular number (or pair) is 0.
Assuming that the random variable is the sum of the two numbers rolled, the answer is 3/36 or 1/12.
Assume the die is fair. What are the numbers on the four sides? How many times are you allowed to roll it? If the four numbers are 1,2,3 and 4 and you want the first three rolls to be 1,3,2 in that order, the probability is 1/4*1/4*1/4 = 1/64.
No numbers are given!