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z = 2.5783

Explanation:

You should make a sketch of the normal curve, with a mean of zero. Now, shade in the region between -z to z as 0.99. The unshade parts must equal 1 - 0.99 or 0.01. Each unshaded parts (left and right tails) are equal, so we need the area of the cumulative normal equal to 0.005, which is -2.5783. I used Excel function: norminv(0.005,0,1).

So from -2.5783 to 2.5784, the area is equal to 0.99 and from minus infinity to

-2.5783, the area is 0.005 and from 2.5783 to infinity, the area is 0.005.

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Q: Find z such 99 percent percent of the area under the standard normal curve lies between -z and z?
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