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Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
78
A z-score requires the mean and standard deviation (or standard error). There is, therefore, not enough information to answer the question.
Bob scored 300 or 700.
Z-score is the x value minus the mean, all divided by the standard deviation; or z=(x-mu)/sigma. The "x" value needs to be given to answer the question.
z-score of a value=(that value minus the mean)/(standard deviation)
score of 92
To get a z-score one needs a standard deviation and a mean as well as the number.
Information is not sufficient to find mean deviation and standard deviation.
A negative Z-Score corresponds to a negative standard deviation, i.e. an observation that is less than the mean, when the standard deviation is normalized so that the standard deviation is zero when the mean is zero.
A z-score cannot help calculate standard deviation. In fact the very point of z-scores is to remove any contribution from the mean or standard deviation.
Stanford-Binet intelligence scale results are measured by calculating the individual's intelligence quotient (IQ). This is done by comparing the person's performance on the test to the performance of others in the same age group. The IQ score is a standardized measure that represents a person's cognitive abilities compared to the general population.
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
mean= 100 standard deviation= 15 value or x or n = 110 the formula to find the z-value = (value - mean)/standard deviation so, z = 110-100/15 = .6666666 = .6667
No. The standard deviation is not exactly a value but rather how far a score deviates from the mean.
The standard deviation.z-score of a value=(that value minus the mean)/(standard deviation)
78