How do you compute C11 5 the 11 and 5 are subscripts?

Answer 1

I'm assuming this is a combinations problem.

nCk = n!/(k!(n-k)!) is the general equation.

In your case n= 11 and k = 5

for 11!/(5!(11-5)!) = 11!/(5!*6!) = (11*10*9*8*7)/(5*4*3*2*1) = 462