Mean: 11.6 Median: 12 Mode: 10, 12, 15, 16, 5 Range: 11
The answer is 15C6 = 15*14*13*12*11*10/(6*5*4*3*2*1) = 5,005
5 6" to 5 11"
I'm assuming this is a combinations problem. nCk = n!/(k!(n-k)!) is the general equation. In your case n= 11 and k = 5 for 11!/(5!(11-5)!) = 11!/(5!*6!) = (11*10*9*8*7)/(5*4*3*2*1) = 462
If you have a plot with 5 10 15 13 and 12 the mean is where you add them all up 5+10+15+13+12=55 then, you divide by how many numbers there are in the plot 5 10 15 13 12 so divide by 5 then you have 11. do you get it?
4x4 = 16 16-5+4 = 15 15-4 = 11
Mean: 11.6 Median: 12 Mode: 10, 12, 15, 16, 5 Range: 11
4/9 ÷ 11/5 = 4/9 x 5/11 = 4x5/9x11 = 20/99
2 and 1/5 = 11/5 = 33/15 33 + 4 = 37/15 33 - 4 = 29/15
(15/5) + (2*4) = 3 + 8 = 11 The parentheses are not actually necessary but help make the sum clearer.
1 + 5/15 = 4/3 or 11/3
5 and 11 are prime. The others are not (3 x 4 =12, 3 x 5 =15, 2 x 11 =22)
NEXT: 11 15 16 12....
Mean = 19.8 -----------[(48 + 11 + 15+14+11) / 5]Median = 14 (middle value of the list)Mode = 11 (most frrequent number)Range = 37 (48 - 11, highest - lowest number)
3/5 and 4/5 are 9/15 and 12/15 therefore 10/15 (same as 2/3) and 11/15 are between
5*64/15 = 5*6 + 5*4/15 (using the distributive property of multiplication over addition). = 30 + 4/3 = 30 + 11/3 = 311/3
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