27 three digit numbers from the digits 3, 5, 7 including repetitions.
In 2 digit numbers : 9, In 3 digit numbers : 18 + 162 = 180, In 4 digit numbers : 2187 + 486 + 27 = 2700, total = 9 + 180 + 2700 + 4 = 2893 simply 2 means:9 3 means:9*2=18 add one 0 so:180 4 means:9*3=27 add two 0 so:2700 then 10000 take four 0:4 total = 9 + 180 + 2700 + 4 = 2893 BY ASHOKKAVI MCA
The sum you require is 4!/2!2!, which is 6. This means there are 6 different two-digit numbers. * * * * * Wrong! The above formula is for the number of combinations, not permutations. However, since the number 23 is different from the number 32, you require permutations and not combinations. There are 4*3 = 12 23, 25, 27, 32, 35, 37, 52, 53, 57, 72, 73, 75.
27
Prob(Sum is odd) = 1/2 Prob(Sum > 6) = 15/36 = 5/12 Prob(Sum is odd or >6) = 27/36 = 3/4
If leading 0s are disallowed, only 27 of them. If leading 0s are allowed then 378.
3897
The two consecutive numbers that have a digit sum of 27 and 1 are 999 and 1000. explanation: 9+9+9= 27 1+0+0= 1 (does not matter how many zeros you add, it will always equal 1) Next number after 999 is 1000.
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
The sum of the numbers 1 through 27 is 378.
3897
98 = 53 + (-3)3 = 125 + (-27)
27
27 three digit numbers from the digits 3, 5, 7 including repetitions.
27
27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797
27