Only one . . . 999 .
27 three digit numbers from the digits 3, 5, 7 including repetitions.
In 2 digit numbers : 9, In 3 digit numbers : 18 + 162 = 180, In 4 digit numbers : 2187 + 486 + 27 = 2700, total = 9 + 180 + 2700 + 4 = 2893 simply 2 means:9 3 means:9*2=18 add one 0 so:180 4 means:9*3=27 add two 0 so:2700 then 10000 take four 0:4 total = 9 + 180 + 2700 + 4 = 2893 BY ASHOKKAVI MCA
The sum you require is 4!/2!2!, which is 6. This means there are 6 different two-digit numbers. * * * * * Wrong! The above formula is for the number of combinations, not permutations. However, since the number 23 is different from the number 32, you require permutations and not combinations. There are 4*3 = 12 23, 25, 27, 32, 35, 37, 52, 53, 57, 72, 73, 75.
27
Prob(Sum is odd) = 1/2 Prob(Sum > 6) = 15/36 = 5/12 Prob(Sum is odd or >6) = 27/36 = 3/4
If leading 0s are disallowed, only 27 of them. If leading 0s are allowed then 378.
3897
The two consecutive numbers that have a digit sum of 27 and 1 are 999 and 1000. explanation: 9+9+9= 27 1+0+0= 1 (does not matter how many zeros you add, it will always equal 1) Next number after 999 is 1000.
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
The sum of the numbers 1 through 27 is 378.
3897
27
27 three digit numbers from the digits 3, 5, 7 including repetitions.
98 = 53 + (-3)3 = 125 + (-27)
27
27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797
The two equal numbers that have a sum of 54 are 27 and 27. When you add these two numbers together, you get 54. This is because the sum of two equal numbers will always be double the value of one of the numbers. In this case, 27 + 27 = 54.