Only one . . . 999 .
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27 three digit numbers from the digits 3, 5, 7 including repetitions.
In 2 digit numbers : 9, In 3 digit numbers : 18 + 162 = 180, In 4 digit numbers : 2187 + 486 + 27 = 2700, total = 9 + 180 + 2700 + 4 = 2893 simply 2 means:9 3 means:9*2=18 add one 0 so:180 4 means:9*3=27 add two 0 so:2700 then 10000 take four 0:4 total = 9 + 180 + 2700 + 4 = 2893 BY ASHOKKAVI MCA
The sum you require is 4!/2!2!, which is 6. This means there are 6 different two-digit numbers. * * * * * Wrong! The above formula is for the number of combinations, not permutations. However, since the number 23 is different from the number 32, you require permutations and not combinations. There are 4*3 = 12 23, 25, 27, 32, 35, 37, 52, 53, 57, 72, 73, 75.
27
Prob(Sum is odd) = 1/2 Prob(Sum > 6) = 15/36 = 5/12 Prob(Sum is odd or >6) = 27/36 = 3/4