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4 digit number having 0 at last position = 9*8*7

=504

4 digit even number having 2 or 4 or 6 or 8 at last position = 8*8*7*4

=1792

(in first position, 0 cannot be fix and in last position one of digit 2,4,6,8 will be fix,

so, number of choice left for first position is 8)

So, total 4 digit even number possible = 504 + 1792

= 2296

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Q: How many 4 digit EVEN numbers have all 4 digits distinct?
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