Oh, what a lovely question! To find the number of 5-number combinations from 59 numbers, we can use a formula called combinations. It's like mixing colors on your palette! The formula is nCr = n! / r!(n-r)!, where n is the total numbers (59) and r is the number of selections (5). So, for 59 numbers choosing 5 at a time, there are 5,006,386 unique combinations waiting to be discovered! Just imagine all the beautiful possibilities that can come from those combinations.
Any 5 from 59 = 5006386
-59
It's just a combination of 59 objects chosen five at a time which means (59*58*57*56*55)/(5*4*3*2*1)=5,006,386. Order does not matter in this calculation, which is why it is a combination not a permutation.
59 of them. Any 2-digit number, from 41 to 99 (inclusive), rounded to the nearest 80 would lead to 80.A:It depends on what you are rounding to. Assuming you are rounding to the nearest tens it would be the following:75, 76, 77, 78, 79, 80, 81, 82, 83, & 84
Well, honey, there are 36 numbers from 10 to 99 where the digits differ by 4. You see, you can start with 10, 21, 32, all the way up to 76, and end with 87 and 98. So, there you have it, 36 numbers that fit the bill.
9
59! / 54! = 59 * 58 * 57 * 56 * 55 = 600766320
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
The number of combinations is 59C6 which is 59!/[6!*(59-6)!] where n! = 1*2*3*...*n So 59C6 = 59*58*57*56*55*54/(6*5*4*3*2*1) = 45,057,474
There are no current NBA or CBA players who wear the number 59. In fact no one has ever wore the number 59. It is not a common jersey number, as many of the jersey numbers happen to feature lower numbers.
If you count zero then you have 60 numbers to choose from for the first slot.If you don't repeat that number you only have 59 for the second slot.then, you only have 58 for the third slot.that would be 205320 ways that it could happen.
Any 5 from 59 = 5006386
1 and 59.
The answer is 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386
59 is a prime number. 1 and 59 are the only divisors of 59.