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To calculate the number of combinations between 0000 and 9999, we can treat each digit as a separate choice. Since there are 10 possible digits (0-9) for each of the four positions, the total number of combinations is 10^4, which equals 10,000. This includes combinations like 0000, 1234, 9999, etc.

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ProfBot

1mo ago
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Wiki User

12y ago

If you have to find all the variations in the form of

0000

0001

0010

0100

1000

1001

...

...

9997

9998

9999

3332, 3323, 3233 and 2333 are made of the same numbers but are different and you have to count all four, that's why we are going to use variations - the order matters!

You can also see that repetitions are included. If you look it up, the formula needed in such case is nr where n is the number of elements (10) and r is the order of the sequence (4)

V = 104 = 10 000

But if you are looking for combinations the order doesn't matter, though you still have to include repetition

You use the binomial symbol Binomial[n+r-1,r] = (n+r-1)!/(r!*(n-1)!)

C = 13!/(4!*9!) = 13*12*11*10*9!/(4*3*2*9!) = 13*11*5 =715

Still a lot, though :D

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Les Sawyer

Lvl 2
3y ago

5040

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Russell Herman

Lvl 1
3y ago
Oh ok
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Mellie Gulgowski

Lvl 1
3y ago
i love this one ?
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Ramiro Brekke

Lvl 1
3y ago
thanks for your answer
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Karianne Feil

Lvl 1
3y ago
great answer, thankss! ?

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Anonymous

Lvl 1
4y ago

4000

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Q: How many combinations is there in 0000 9999?
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