How many combinations is there in 0000 9999?

Answer 1

To calculate the number of combinations between 0000 and 9999, we can treat each digit as a separate choice. Since there are 10 possible digits (0-9) for each of the four positions, the total number of combinations is 10^4, which equals 10,000. This includes combinations like 0000, 1234, 9999, etc.

Answer 2

Well, isn't that a happy little question! Let's see here. With four digits ranging from 0 to 9, there are 10 options for each digit. So, if we multiply 10 options for each of the four digits together, we get a total of 10,000 possible combinations from 0000 to 9999. Just imagine all the beautiful possibilities waiting to be discovered!

Answer 3

If you have to find all the variations in the form of

0000

0001

0010

0100

1000

1001

...

...

9997

9998

9999

3332, 3323, 3233 and 2333 are made of the same numbers but are different and you have to count all four, that's why we are going to use variations - the order matters!

You can also see that repetitions are included. If you look it up, the formula needed in such case is nr where n is the number of elements (10) and r is the order of the sequence (4)

V = 104 = 10 000

But if you are looking for combinations the order doesn't matter, though you still have to include repetition

You use the binomial symbol Binomial[n+r-1,r] = (n+r-1)!/(r!*(n-1)!)

C = 13!/(4!*9!) = 13*12*11*10*9!/(4*3*2*9!) = 13*11*5 =715

Still a lot, though :D

Answer 4

5040

Answer 5

4000