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Well, honey, if you want to know the number of 4-digit combinations with no repeated numbers, it's pretty simple. You start with 9 choices for the first digit (can't be 0), then 9 choices for the second digit (can't repeat the first), 8 choices for the third digit, and finally 7 choices for the fourth digit. Multiply those together and you get 4536 possible combinations. Easy peasy lemon squeezy!
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ViviIn decimal, 4 digits ( 0 - 9) you can represent any number from 0000 to 9999. That is 10,000 unique number combinations. Incidentally, the number of unique cominations is 10 to the 4th power. In binary, 4 digits (0 - 1) can represent 16 different cominations from 0000 - 1111. This is given by 2 to the 4th power
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How many 3 digit numbers can be formed from the digits 357 with any digit repeated?
27 three digit numbers from the digits 3, 5, 7 including repetitions.
How many 4 digit numbers can be formed from the digits 7341 if none of the digits can be repeated?
24
How many 4-digit pin numbers are available if no number is repeated?
A lot. And there is akways the code. 1234
How many 5 digit numbers can be formed out of 56789 if they can be repeated?
Five numbers (5, 6, 7, 8, 9) can be selected for each of the 5 digits. So, there are 5*5*5*5*5 or 55 or 3125 five digit numbers.
How many 5 digit combinations for numbers 1- 25?
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
