There are 5 ways to choose the first letter, 4 ways to pick the second letter, 3 ways to select the third, 2 options for the fourth letter leaving just one way to pick the final letter.
The number of arrangements are thus 5 x 4 x 3 x 2 x 1 = 120
64 different arrangements are possible.
There are 4 letters in IOWA, all non repeating. Arrangements are 4! or 24.
40,320
If you pick from each of the possible letters at each stage, then there are 5 possible options for the first letter. Then there are 4 possible options for the second. Then there are 3 possible options for the 3rd and so on. This leaves us with 5x4x3x2 = 120 different arrangements. However, each arrangement has been counted twice, as it doesn't matter which way around the Os go. So to get the true answer, we need to divide by 2. 120/2 = 60, and therefore the number of different arrangements of the letters in the word COLOR is 60.
There are 5!/2! = 60 arrangements.
120
from itertools import permutationsfrom string import joinarrangements = [ ]for p in permutations ( 'ugccsir', 6 ) :arrangement = join ( p, '' )if 'ui' in arrangement :continueif not arrangement in arrangements :arrangements . append ( arrangement )print len ( arrangements )The above Python code gives a result of 2,220.
There are 5*4*3 = 60 arrangements.
There are 172 different arrangements.
64 different arrangements are possible.
There are 6! = 720 different arrangements.
There are (1*5*4)*(3*2*1) = 120 arrangements.
There are 7!/(2!*2!) = 1260 arrangements.
6! = 6x5x4x3x2x1 = 720 arrangements
There are 4 letters in IOWA, all non repeating. Arrangements are 4! or 24.
Answer: 7P4 = 840 arrangementsNumber of letters in the word ENGLISH : 7Number of letters to take: 4Number of arrangements:= 7P4= 7!/(7-4)!= 5040/6= 840
40,320