1 byte is 8 bits. That's 8 1s or 0s.
2 bytes is 8*2=16 bits (1s/0s).
That is 2^16=65536 possibilities.
Therefore, there are 65,536 different combinations with 2 bytes.
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Four of them.
if its not alphanumeric, 999999 variations
There are 2300 possible combinations.
18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.
Four outcomes, three combinations.