10,000
whenever you have a question like this, just multiply the two numbers together and you got your answer.
Well, isn't that just a happy little question! With 99 numbers, the number of combinations can be quite a lot. You see, when you have that many numbers, the possibilities are endless, just like the colors on our palette. So go ahead, explore those combinations and see where your imagination takes you!
I will presume that you are using the space of integers (as there are in infinite number of real or even rational numbers between 1 and 15). There are 15 integers on the interval of [1,15] and we want to find all possible combinations of 6 numbers from this set. We use a combination, 6C15= 15! / (6! * (15 - 6)!) = 15! / (6! * 9!) If you do not have a calculator which does factorials or combinations, then you can do some cancellations to make the computation a little easier: 15! = 15 * 14 * 13 * 12 * 11 * 10 * 9! so we can cancel the 9!, which leaves us with: 15 * 14 * 13 * 12 * 11 * 10 / 6! This is still going to involve the multiplication and division of very large numbers, so I took the pansy route and just used a calculator and got: 5,005 different possible combinations.
There is just 1 combination of 8 numbers taken 8 at a time.
Oh, isn't that just a happy little question! With 36 different numbers, you can create a whopping 1,073,741,824 unique combinations. Just imagine all the beautiful possibilities waiting to be explored on your canvas of numbers. Remember, there are no mistakes, only happy accidents in the world of math!
Just 1.
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
Just one. unless you count 123456 different from 132456 then there are 46656 * * * * * But you cannot count 123456 as different from 132456 since it is NOT a different combination. And the question was about combinations.
To calculate the number of combinations of 5 numbers possible from 1 to 20, we use the formula for combinations, which is nCr = n! / (r!(n-r)!). In this case, n = 20 and r = 5. Plugging these values into the formula, we get 20! / (5!(20-5)!) = 20! / (5!15!) = (20x19x18x17x16) / (5x4x3x2x1) = 15,504 possible combinations.
To calculate the combinations for the numbers 2, 6, and 8, we need to use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, we have 3 numbers (n=3) and we want to choose 2 of them (r=2). So, the combinations would be 3C2 = 3! / 2!(3-2)! = 3. Therefore, the combinations for 2, 6, and 8 are (2, 6), (2, 8), and (6, 8).
Oh, isn't that just lovely? You can create so many beautiful combinations using the numbers 1 through 9. Just think of all the possibilities waiting to be discovered! Keep exploring and let your imagination run wild with all the different combinations you can come up with.
whenever you have a question like this, just multiply the two numbers together and you got your answer.
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
Well, isn't that just a happy little question! With 99 numbers, the number of combinations can be quite a lot. You see, when you have that many numbers, the possibilities are endless, just like the colors on our palette. So go ahead, explore those combinations and see where your imagination takes you!
I will presume that you are using the space of integers (as there are in infinite number of real or even rational numbers between 1 and 15). There are 15 integers on the interval of [1,15] and we want to find all possible combinations of 6 numbers from this set. We use a combination, 6C15= 15! / (6! * (15 - 6)!) = 15! / (6! * 9!) If you do not have a calculator which does factorials or combinations, then you can do some cancellations to make the computation a little easier: 15! = 15 * 14 * 13 * 12 * 11 * 10 * 9! so we can cancel the 9!, which leaves us with: 15 * 14 * 13 * 12 * 11 * 10 / 6! This is still going to involve the multiplication and division of very large numbers, so I took the pansy route and just used a calculator and got: 5,005 different possible combinations.