Set up the problem as: y=number of yellow marbles & 4y=number of blue marbles. 40=y+4y or 40=5y or y=8. Therefore number of blue marbles is 4*8 = 32.
48 marbles
at least 39 blue marbles
12 blue marbles
102/6=17*5=85 Harry=85 marbles. Jack=17 marbles.
10 ?
Set up the problem as: y=number of yellow marbles & 4y=number of blue marbles. 40=y+4y or 40=5y or y=8. Therefore number of blue marbles is 4*8 = 32.
48 marbles
at least 39 blue marbles
There is insufficient information in the question to answer it. You need to specify the population set, i.e. how many red and yellow marbles, and how many total marbles, there are. Please restate the question./
There are at least 11 green marbles in the bag.
The probability of selecting 4 red marbles or 5 blue marbles depends on how many marbles there are altogether, and how many of the total number of marbles are red and how many are blue.
12
He will have 13 blue marbles and 10 green marbles.
100
He has 10 green marbles.
10 Green marbles, 13 Blue marbles.