48 marbles
at least 39 blue marbles
Set up the problem as: y=number of yellow marbles & 4y=number of blue marbles. 40=y+4y or 40=5y or y=8. Therefore number of blue marbles is 4*8 = 32.
2 out of 3 times 3 out of 5
D+J = 328 M+D = 176 J = 5M D+5M = 328 D+M = 176 subtract 4M = 152 M = 38 D = 176-38 = 138
48 marbles
at least 39 blue marbles
If you had a bag of marbles, and there were two colours - red and green - and the ratio of the coloured marbles is two times the amount of green marbles to red marbles, you would have a ratio of 2:1
Set up the problem as: y=number of yellow marbles & 4y=number of blue marbles. 40=y+4y or 40=5y or y=8. Therefore number of blue marbles is 4*8 = 32.
The marbles are now in a ratio of 4:1 between them. Ben has 72 marbles Bill has 18 marbles
2 out of 3 times 3 out of 5
i think it's 6x7=42 any1 else think that's right ;)
48 times.
They had altogether at first 176 marbles (Mar has 44 and Jay has 132).
They started off with A = 128, B = 32.
Depends on the color of the marbles, or more specifically, it depends upon how many of the marbles are blue. If 0 marbles are blue, then the chance is 0. If 1 marble is blue, then the chance is 1/4. If 2 marbles are blue, then the chance is 1/2. If 3 marbles are blue, then the chance is 3/4. If 4 marbles are blue, then the chance is 1. These probabilities assume that you draw only once. The other possibilities are that you draw twice, or three times, or four times. If drawing multiple times, it can be done by putting back each marble after it was drawn, or by keeping it out after it has been drawn.
make it out of 100, so 40 times 2.5 equals 100 and 18 times 2.5 equals... 45 so its 45 percent