The answer is 20C4 = 20*19*18*17/(4*3*2*1) = 4845
1,19,23,27,30 ( divided by ) 5= 20
There are many answers. Here is one: 58 and 20
You can just find the factors: 1x30 2x15 3x10 5x6 so that's 8 numbers
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
Three sets
1,2,3,4,5,6,10,12,15,20,30,60
To find how many three-digit numbers are multiples of 20, we need to determine the range of three-digit numbers divisible by 20. The smallest three-digit number divisible by 20 is 100, and the largest is 980. To find the count of numbers in this range, we can divide the largest number by 20 and subtract the result of dividing the smallest number by 20, then add 1 to account for the inclusive range. Therefore, the number of three-digit multiples of 20 is (980/20) - (100/20) + 1 = 49 - 5 + 1 = 45.
There are infinitely many whole numbers which are less than 20. Start with 19 and go back, beyond 0, to negative infinity.
The numbers 1-20 are on a dart board so there are twenty numbers.
Any of their multiples
35 times equally no numbers left over.
1, 2, 4, 5, and 10 can go into 20.
The HCF of 39 and 20 is 1
20 numbers
20 numbers
how many odd numbers is there between 20 and 158