Q: How many outcomes are in the sample space for rolling 4 dice?

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There are 36.

The set of all possible outcomes of a random experiment is nothing but sample space usually denoted by S. we can also call it as event. For example our experiment is rolling a dice, then our sample space is S= {1,2,3,4,5,6}

The sample space has 36 elements (the total number of outcomes by rolling the two dice). There are 6 double outcomes: (1,1), (2,2), (3,3), (4,4), (5,5) and (6,6). There are 5 outcomes whose sum is 6: (1,5), (5,1), (2,4), (4, 2), and (3,3). The probability of rolling doubles OR the sum of 6 is 6/36 + 5/36 = 11/36.

I dont no

There are 36 outcomes rolling two dice.

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11 outcomes if the dice are indistinguishable, 36 otherwise.

There are 36.

Assuming traditional cubic dice, the sample space consists of 216 points.

Not sure about the relevance of sizzle! The size of the sample space is 46656.

The sample space for 1 roll is of size 6.

impossible or 1/6 * * * * * No! The sample space refers to the set of possible outcomes, not the probability of any one outcome.

1, 2, 3, 4, 5, 6

5 and 1.

The set of all possible outcomes of a random experiment is nothing but sample space usually denoted by S. we can also call it as event. For example our experiment is rolling a dice, then our sample space is S= {1,2,3,4,5,6}

There is 6 possible outcomes per roll of a die. So, there are 6*6*6*6 outcomes or 64 or 1296 possible outcomes.

If we roll 2 dice simultanosly the sample space consists of 6 rows and 6 col so the answer is 6*6 i.e 36 elements.If we roll 6 dice simultanosly the sample space consists of 36 rows and 36 col so the answer is 36*36 i.e 1296 elements.

The sample space has 36 elements (the total number of outcomes by rolling the two dice). There are 6 double outcomes: (1,1), (2,2), (3,3), (4,4), (5,5) and (6,6). There are 5 outcomes whose sum is 6: (1,5), (5,1), (2,4), (4, 2), and (3,3). The probability of rolling doubles OR the sum of 6 is 6/36 + 5/36 = 11/36.