The possible outcomes for rolling a number cube twice are:
1,1 1,2 1,3 1,4 1,5 1,6 2,1 2,2 2,3 2,4 2,5 2,6 3,1 3,2 3,3 3,4 3,5 3,6 4,1 4,2 4,3 4,4 4,5 4,6 5,1 5,2 5,3 5,4 5,5 5,6 6,1 6,2 6,3 6,4 6,5 6,6
This is a total of 36 different combinations.
There are 36 possible outcomes.
6 possible numbers to land on the first time, 6 possible numbers to land on the second time, 6x6=36
When a number cube is rolled twice, there are 36 possible outcomes. (1,1),(1,2),....(6,6). (3,3) occurs only once. Therefore, the probability of rolling a 3 both times is 1/36.
When rolling a number cube (a six-sided dice) twice, the sample space consists of all possible outcomes from both rolls. Since each roll has 6 possible outcomes, the total number of outcomes for rolling the number cube twice is 6 x 6 = 36. The sample space would be {1-1, 1-2, 1-3, ..., 6-5, 6-6} representing all possible combinations of the two rolls.
Well what does the spinner look like
There are 36 possible outcomes.
36
6 possible numbers to land on the first time, 6 possible numbers to land on the second time, 6x6=36
When a number cube is rolled twice, there are 36 possible outcomes. (1,1),(1,2),....(6,6). (3,3) occurs only once. Therefore, the probability of rolling a 3 both times is 1/36.
If a spinner has six possible outcomes, then there are 36 (62) permutations of outcomes from spinning it twice.
It is 0.722... recurring.
When rolling a number cube (a six-sided dice) twice, the sample space consists of all possible outcomes from both rolls. Since each roll has 6 possible outcomes, the total number of outcomes for rolling the number cube twice is 6 x 6 = 36. The sample space would be {1-1, 1-2, 1-3, ..., 6-5, 6-6} representing all possible combinations of the two rolls.
Well what does the spinner look like
When rolling a six-sided die, there is only one way for both numbers to be the same, which occurs when the die is rolled twice and both rolls result in the same number (1-1, 2-2, etc.). There are a total of 36 possible outcomes when rolling two dice (6 sides for the first die multiplied by 6 sides for the second die). Therefore, the probability that both numbers are the same is 6 favorable outcomes (one for each number) out of 36 total outcomes, which simplifies to 1/6.
The odds of corerectly predicting 1 number on a dice with 1 throw is 1 in 6. Predicting the same number to appear in two throws, its 1 in (6 * 6) 36 > Same deal with the coin, except less options, so 1 in (2 * 2) 4
There are four outcomes possible. Both even, both odd, and one of each twice. So, in one roll, it looks like your chances are 1 in 4. Is that what you are after?
The odds of of an odd number on the first role are 3/6 since the odds are 1,3, and 5 and there are 6 numbers. The odds of an even are the same. Since they are independent we can multiply the two probabilities and the answer is .5x.5=.25 If this is confusing, consider the sample space where I denote O for an odd number and E for an even number. In two rolls you can have: OO, OE,EO, OO So there are 4 possible outcomes. We are interested only in OE which is 1 of the 4 outcomes so the probability of this happening is 1 in 4 or .25.