0
A single six sided die is rolled twice What is the probability of rolling an odd number on the first roll and an even number on the second roll?
The odds of of an odd number on the first role are 3/6 since the odds are 1,3, and 5 and there are 6 numbers. The odds of an even are the same. Since they are independent we can multiply the two probabilities and the answer is .5x.5=.25 If this is confusing, consider the sample space where I denote O for an odd number and E for an even number. In two rolls you can have: OO, OE,EO, OO So there are 4 possible outcomes. We are interested only in OE which is 1 of the 4 outcomes so the probability of this happening is 1 in 4 or .25.
What else can I help you with?
A six sided die is rolled twice what is the probability of rolling either an even number on the first roll or a 1 on the second roll the answer is 7 over 12 but I can't figure out how to get there?
The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.The probability of rolling a 1 on the second roll is 1/6.If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:3/6 + 1/6 - 3/36= 18/36 + 6/36 - 3/36= 21/36= 7/12
What is the probability when you roll two dice that you roll an odd number on the first die and a 1 on the second die?
The probability when you roll two dice that you roll an odd number on the first die and a 1 on the second die is 1 in 12. The two die are sequentially unrelated, so you can consider them separately. The probability of rolling an odd number is 3 in 6, or 1 in 2. The probability of rolling a 1 is 1 in 6. Multiply the two probabilities together and you get 3 in 36, or 1 in 12.
What are the chances of rolling the number seven with two dice?
There are 36 permutations of two dice. Of these, six have a sum of seven. The probability, then, of rolling a seven on two dice is 6 in 36, or 1 in 6, or about 0.1667.It does not matter if two dice are rolled one time, or if one die is rolled two times. The probability of rolling a sum of 7 is still about 0.1667.The first thing to do is to identify all possible combinations which could give the sum of 7. These are: 6 and 1, 5 and 2, 4 and 3, 3 and 4, 2 and 5, and 1 and 6.Thus there are 6 possible combinations.For each of these combinations, the probability of getting the 1st number correct is 1/6 and the probability of getting the second number correct is 1/6, and so the overall probability of the combination is 1/36There are 6 ways to get 7 though so 6x 1/36 = 1/6Which means the probability that 2 dice rolls will add up to 7 is 1/6
A six sided cube numbered 1 through 6 is rolled 120 timesThe number 4 comes up 19 times what is the theoretical probability of rolling a 4?
Because we are only modeling one event, all six outcomes of the die are equally possible. The probability of rolling a four (or, for that matter, any number) is 1/6, or .166666 repeating. Now, since we are modeling 120 rolls, the theoretical number of outcomes of four (or, again, any number) is 1/6 * 120 = 20 outcomes. The second sentence of the problem is unnecessary.
What is the probability of rolling a 6 and a 4?
The probability of rolling any specific number will be 1/6, as there are 6 equally likely numbers on a dice. The probability of rolling a 6 then a 4 will thus be 1/6 x 1/6 which gives 1/36. Note, however, that there are two ways the dice can be ordered. The first can be 6 and the second 4, or the other way around. So multiply the above probability by 2 and you get 1/18. Thus the probability of rolling a 6 and a 4 is 1/18
What if two dice are rolled find probabliity that an even number is rolled on one die and an odd number is rolled on the second die?
The probability of rolling an even die and then an odd die is (3 in 6) times (3 in 6), which is the same as (1 in 2) times (1 in 2), which is the same as 0.5 time 0.5, which is 0.25.
A six sided die is rolled twice what is the probability of rolling either an even number on the first roll or a 1 on the second roll the answer is 7 over 12 but I can't figure out how to get there?
The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.The probability of rolling a 1 on the second roll is 1/6.If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:3/6 + 1/6 - 3/36= 18/36 + 6/36 - 3/36= 21/36= 7/12
What is the probability of rolling an even number on a die and rolling an odd number on a second roll of the same die?
0.25 ( P = 0.5 each time)
What is the probability of rolling a 6 the first time and a 1 the second time?
What is the probability of rolling a 6 the first time and a 1 the second time
Find the probability of rolling a 2 on a number cube and then an even number on two consecutive rolls of a number cube?
1/6,3/6 ----------------------------------------------------------------------------------------------------- The probability of rolling a 2 is: P(2) = 1/6 The probability of rolling an even number is: P(even) = 1/2 The result on the second roll is independent of the result in the first roll. The probability of rolling a 2 and then rolling an even number is: P(2,even no.) = (1/6) ∙ (1/2) = 1/12 = 0.08333... ≈ 8.33%
Rolling three dice what is the probability of rolling an odd number?
The probability that, when rolling three dice none will come up odd is broken down by the probability that on odd roll will occur as an independent event. Rolling the first die has a probability of 3/6 that it will be odd. Rolling the second has the probability of 3/6 that it will be odd. Rolling the third has a probability of 3/6 will be odd. Rolling three and coming up with odd is really the probability that no odd numbers occurred, so therefore an even number DID happen (3/6), and an even number DID happen (3/6), and an even number DID happen (3/6). That's really just 1 - (3/6^3) or simplified 1 - (1/2^3). So therefore the probability that an odd number occurred in 3 die rolls is about 87.5%.
What is the probability of rolling a prime number and the probability of rolling a number greater than 1 on two rolls fo a die?
First you need to work out the probability of rolling a prime number. The prime numbers on a die are 2, 3 and 5. Thus the probability of rolling a prime number is 3/6 which can be simplified to 1/2. The probability of rolling a number greater than 1 is 5/6. The probability of rolling one on one dice and one on the other is therefore 1/2 x 5/6 = 5/12. There are two possible ways round these options could come though. You might get the number greater than one on the first roll, and the prime on the second. Thus we need to multiply the probability by 2, which gives us the final answer of 5/6.
What is the probability of rolling a prime number first and a composite number second with a fair number cube?
It is 1/2*1/3 = 1/6
What is the probability of rolling a 2 and then a 3 with 6-sised cubes?
The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.
What is the probability of rolling a 2 on the first dice and an odd number on the second dice?
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
What is the probability of throwing just one one with two dice?
The probability of throwing just one one with two dice can be calculated by considering the different ways it can occur. There are two ways to get one one: rolling a one on the first die and any number on the second die, or rolling any number on the first die and a one on the second die. There are a total of 36 possible outcomes when rolling two dice, so the probability is 2/36, which simplifies to 1/18.
If a single die is rolled twice What is the probability of getting a 3 the first time and a 5 the second time?
The probability of rolling a 3 on a single die is 1/6. Similarly, the probability of rolling a 5 on a single die is also 1/6. When rolling the die twice, the probabilities are independent events, so you multiply the probabilities together: (1/6) * (1/6) = 1/36. Therefore, the probability of rolling a 3 the first time and a 5 the second time is 1/36.
