It depends on whether the order of the numbers is important or not. For example, if 123456 is seen as a different code to 213456 then there are many more possible solutions.
If the order is unimportant, the number of possible combinations is equal to
binomial coefficient(15,6) = 5005
If the order is important, then the number of possible permutations is equal to
15! = ~1.3x1012
Too many to list here-see below.
if its not alphanumeric, 999999 variations
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The number of combinations is the number of characters - in this case, 10 - raised to the power if the number of places. So using only the numerals zero through nine, and a 10-character PIN, there are 10 raised to the tenth power combinations, or 1,000,000,000 different possibilities.
There are five digits all together. The number of ways of arranging them is5 x 4 x 3 x 2 x 1 = 120 .But the three 2s can be arranged in 3 x 2 = 6 different ways and they all look the same.And the two 4s can be arranged in 2 different ways and they look the same.So out of the 120 different ways of arranging all five, there's a group of sixfor every possible arrangement of the 2s that all look the same, and there'sa group of two for each possible arrangement of the 4s that both look thesame.The number of combinations that look different is 120/(6 x 2) = 10 .And here they are:2 2 2 4 42 2 4 2 42 2 4 4 22 4 2 2 42 4 2 4 22 4 4 2 24 2 2 2 44 2 2 4 24 2 4 2 24 4 2 2 2
If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.
Too many to list here-see below.
if its not alphanumeric, 999999 variations
Yes its possible. If a person spent the time to create such a powerful code that covered all possible combinations of attack then it would be a real life situation of digital fortress if it got out. To do this may take over a lifetime to make the basics and all of the possible combinations of the code.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
There are 26 letters in the alphabet.If letters may be repeated in the airport code, then there are (26 x 26 x 26) = 17,576 possibilities.If adjacent letters can't be duplicates, then there are (26 x 25 x 25) = 16,250 possibilities.If all three letters must be different, then there are (26 x 25 x 24) = 15,600 possibilities.
-5
it is 336
The answer is five factoral (5!) which is 120.
Chess. There are more possible games of chess than atoms in the universe.
combining the 26 letters with the 10 digits you have 36 possible characters to choose from to go into 16 slots. Grab the nearest scientific calculator, or use google or whatever you like, and use the permutation function nPr, inputting 36P16 you get 1.529x1023 different possible combinations to 4 significant figures. Alternatively if you don't have the use of the nPr function you can use the formula n!/(n-r)! where n is the characters available and r is the amount of slots they have to go in.
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