Best Answer

There are five digits all together. The number of ways of arranging them is

5 x 4 x 3 x 2 x 1 = 120 .

But the three 2s can be arranged in 3 x 2 = 6 different ways and they all look the same.

And the two 4s can be arranged in 2 different ways and they look the same.

So out of the 120 different ways of arranging all five, there's a group of six

for every possible arrangement of the 2s that all look the same, and there's

a group of two for each possible arrangement of the 4s that both look the

same.

The number of combinations that look different is 120/(6 x 2) = 10 .

And here they are:

2 2 2 4 4

2 2 4 2 4

2 2 4 4 2

2 4 2 2 4

2 4 2 4 2

2 4 4 2 2

4 2 2 2 4

4 2 2 4 2

4 2 4 2 2

4 4 2 2 2

Q: How many combinations are there for a 5 digit code using 3 2s and 2 4s?

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if its not alphanumeric, 999999 variations

120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.

Too many to list here-see below.

Just 1.

Any 6 from 51 = 18,009,460 combinations

Related questions

if its not alphanumeric, 999999 variations

Number of 7 digit combinations out of the 10 one-digit numbers = 120.

216

There are 840 4-digit combinations without repeating any digit in the combinations.

There are 5,040 combinations.

There are 210 4 digit combinations and 5040 different 4 digit codes.

120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.

1296 or (6^4)

the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822

Too many to list here-see below.

Too many to list here-see below.

There are twelve possible solutions using the rule you stated.