There are five digits all together. The number of ways of arranging them is
5 x 4 x 3 x 2 x 1 = 120 .
But the three 2s can be arranged in 3 x 2 = 6 different ways and they all look the same.
And the two 4s can be arranged in 2 different ways and they look the same.
So out of the 120 different ways of arranging all five, there's a group of six
for every possible arrangement of the 2s that all look the same, and there's
a group of two for each possible arrangement of the 4s that both look the
same.
The number of combinations that look different is 120/(6 x 2) = 10 .
And here they are:
2 2 2 4 4
2 2 4 2 4
2 2 4 4 2
2 4 2 2 4
2 4 2 4 2
2 4 4 2 2
4 2 2 2 4
4 2 2 4 2
4 2 4 2 2
4 4 2 2 2
if its not alphanumeric, 999999 variations
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
Too many to list here-see below.
Just 1.
Any 6 from 51 = 18,009,460 combinations
if its not alphanumeric, 999999 variations
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
216
There are 840 4-digit combinations without repeating any digit in the combinations.
There are 5,040 combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
1296 or (6^4)
the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
Too many to list here-see below.
Too many to list here-see below.
There are twelve possible solutions using the rule you stated.