You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations.
Permutations of five objects is 5!, five gives 5!, so the total permutations are:
5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations
The answer depends on how many books on each subject there are.
9 x 8 x 7 x 6 x 5
The number of permutations of five things taken five at a time is five factorial, or 120.
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
Assuming that each of the nine books is unique, that there are only nine positions open on the given shelf, and that each book can fit in each position, the answer is 9! (nine factorial) which is equal to 362,880. If the nine books are not all unique (i.e. there are two of the same book), the number should decrease taking into effect that reversing the positions of the identical books makes no overall change. If there is one additional position, the number should increase to 10! or 3,628,800. If there is more than one additional position, the number will still increase, but not to 11! or 12! since both open spaces are reversible just like the identical books.
The answer depends on how many books on each subject there are.
it depends on the shelf of course
Slowly and methodically, I arranged the books on the shelf.
The number of ways that 15 books can be arranged on a shelf is the same as the number of permutations of 15 things taken 15 at a time. This is 15 factorial, or 15!, and is 1,307,674,368,000.
There are 2*5! = 240 ways.
The number of different ways to arrange six books on a shelf is calculated using the factorial of the number of books. This is represented as 6!, which equals 6 × 5 × 4 × 3 × 2 × 1. Thus, there are 720 different ways to arrange six books on a shelf.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
9 x 8 x 7 x 6 x 5
The number of permutations of five things taken five at a time is five factorial, or 120.
Stack the books on the shelf that is higher in height.
Leaning
6! = 1 x 2 x 3 x 4 x 5 x 6.