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You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations.

Permutations of five objects is 5!, five gives 5!, so the total permutations are:

5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations

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How many ways can 8 books be arranged on a shelf such that books on biology history and programming are never together?

The answer depends on how many books on each subject there are.


How many ways can 9 books be arranged on a shelf if there is only room for 5 of the books?

9 x 8 x 7 x 6 x 5


How many different ways can five books be arranged on a shelf?

The number of permutations of five things taken five at a time is five factorial, or 120.


How many different ways can you arrange 5 out of 7 books on a book shelf?

There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520


How many ways can 9 books be arranged on a shelf?

Assuming that each of the nine books is unique, that there are only nine positions open on the given shelf, and that each book can fit in each position, the answer is 9! (nine factorial) which is equal to 362,880. If the nine books are not all unique (i.e. there are two of the same book), the number should decrease taking into effect that reversing the positions of the identical books makes no overall change. If there is one additional position, the number should increase to 10! or 3,628,800. If there is more than one additional position, the number will still increase, but not to 11! or 12! since both open spaces are reversible just like the identical books.

Related Questions

How many ways can 8 books be arranged on a shelf such that books on biology history and programming are never together?

The answer depends on how many books on each subject there are.


How many ways can seven books be arranged on a shelf if one of the books is an algebra text and it must be in the center?

it depends on the shelf of course


How do you write the sentence with the word Methodically?

Slowly and methodically, I arranged the books on the shelf.


How many different ways can 15 books be arranged vertically side by side on a shelf?

The number of ways that 15 books can be arranged on a shelf is the same as the number of permutations of 15 things taken 15 at a time. This is 15 factorial, or 15!, and is 1,307,674,368,000.


How many ways can six different books be arranged on a shelf it one of the books is a novel that must be on an end?

There are 2*5! = 240 ways.


How many different ways can six books be arranged on a shelf?

The number of different ways to arrange six books on a shelf is calculated using the factorial of the number of books. This is represented as 6!, which equals 6 × 5 × 4 × 3 × 2 × 1. Thus, there are 720 different ways to arrange six books on a shelf.


There are Five books on a shelf. How many different ways to arrange the books?

120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer


How many ways can 9 books be arranged on a shelf if there is only room for 5 of the books?

9 x 8 x 7 x 6 x 5


How many different ways can five books be arranged on a shelf?

The number of permutations of five things taken five at a time is five factorial, or 120.


Put the books on the TALL shelf?

Stack the books on the shelf that is higher in height.


How are magazines arranged on a supermarket shelf?

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In how many different ways can 6 books be arranged on a shelf?

6! = 1 x 2 x 3 x 4 x 5 x 6.