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How many ways can 9 books be arranged on a shelf so that 5 of the books are always together?
You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations. Permutations of five objects is 5!, five gives 5!, so the total permutations are: 5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations
How many ways can five differently colored marbles be arrange in a row?
They can be arranged 5! or 120 ways.
How many combinations are there for a 5 digit code using 3 2s and 2 4s?
There are five digits all together. The number of ways of arranging them is5 x 4 x 3 x 2 x 1 = 120 .But the three 2s can be arranged in 3 x 2 = 6 different ways and they all look the same.And the two 4s can be arranged in 2 different ways and they look the same.So out of the 120 different ways of arranging all five, there's a group of sixfor every possible arrangement of the 2s that all look the same, and there'sa group of two for each possible arrangement of the 4s that both look thesame.The number of combinations that look different is 120/(6 x 2) = 10 .And here they are:2 2 2 4 42 2 4 2 42 2 4 4 22 4 2 2 42 4 2 4 22 4 4 2 24 2 2 2 44 2 2 4 24 2 4 2 24 4 2 2 2
What is the probability that the birthdays of five persons chosen at random will fall in twelve different calendar months?
The probability that the birthdays of five persons chosen at random will fall in twelve different calender months is zero. You would need at least twelve persons to have a non zero probability.
How many different five-letter arrangements can be made from the letters in the name EULER?
There are 5!/2! = 60 arrangements.
There are Five books on a shelf. How many different ways to arrange the books?
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
How many ways can five textbooks be arranged on a shelf?
5*4*3*2*1=120 ways
How many different ways can five brands of sodas be displayed on a shelf one at a time in a row?
One row of 5 different brands with each type being represented can be arranged in 5x4x3x2x1= 120 ways
How many ways can 9 books be arranged on a shelf so that 5 of the books are always together?
You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations. Permutations of five objects is 5!, five gives 5!, so the total permutations are: 5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations
If a teacher has one -hundred-eighty five books and she puts forty - five books on each shelf how many shelfs have 45 books?
4 have exactly 45 but you would need 5 shelves to fit them all
In how many different ways can five runners be arranged?
5! = 120
The Rig-Veda has five parts?
No. The Rig Veda is a collection of 1028 hymns which are arranged in 10 books. the hymns are called Sutras and the books are called Mandalas.
How do you make a sentence with the word library's?
The library's books are arranged in alphabetical order.
Five devices arranged in a mesh topology?
gdfbjggfegfgafbjyegbahfyugfjhafb
Twenty five plants on five shelves Each shelf has two more plants than the shelf above it How many plants are on each shelf?
Top shelf has one plant, second shelf has three plants, third shelf has five plants, fourth shelf has seven plants and the bottom shelf has nine plants. 1+3+5+7+9=25
Who uses the first five books of the Bible as their whole Bible?
one religion does not use the first five books exclusively. The Jews have different names for the first five books though, like the Pentateuch or the Torah
How many ways can 10 books be arranged if 4 math books are keeped toghter?
While massaging the question into some form that can be answered,I'm assuming:-- exactly 4 of the 10 books are math books-- the other 6 are not math books-- you're asking how many different ways all 10 can be arrangedon the shelf while keeping the math books all together.If that's your question, then the answer is as follows. If that's not your question,then the following is the answer to my question but it won't help you at all :The 10 books are really only 7 units to be arranged ... 6 random books, andone unit comprised of math books that might as well be glued together becausethey can't separated. So the shelf arrangement involves lining up 7 things.The first can be any one of the seven. For each of those . . .The second one can be any one of the remaining six. For each of those . . .The third can be any one of the remaining five. For each of those . . ...etc.Total number of possible arrangements is (7 x 6 x 5 x 4 x 3 x 2) = 5,040 ways.
