5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
30 ways.
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
Consider one placement at a time. The first book on the shelf could be any of seven. The second could be any of the remaining six. This continues with the rest. The total combinations are: 7! = 7*6*5*4*3*2*1 = 5040
The answer depends on how many books on each subject there are.
792 different groups of 5 books, in 95,040 different sequences.
To arrange 3 algebra books and 3 geometry books on a shelf so that no two books of the same type are next to each other, you can use the concept of permutations. There are 3! ways to arrange the algebra books and 3! ways to arrange the geometry books. This gives a total of 3! * 3! = 36 ways to arrange the books on the shelf such that no two books of the same type are next to each other.
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because of gravity. i think
30 ways.
Alternate them.
The answer to this one is 24. You can do this mathematically by 4*3*2*1.
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
Yes. They are real.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
There are 5! (that is, 120) distinct ways to arrange five items. Only 1 of them will have the books in alphabetical order by title. So the probability that it happens by random is 1/120.
Choose 3 then 2 then 1; 3*2*1 = 6 ways.
The answer would be 7! or (7*6*5*4*3*2*1)=5040