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5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.

Q: How many ways can you arrange 5 books on a shelf order is important?

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30 ways.

There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520

Consider one placement at a time. The first book on the shelf could be any of seven. The second could be any of the remaining six. This continues with the rest. The total combinations are: 7! = 7*6*5*4*3*2*1 = 5040

The answer depends on how many books on each subject there are.

792 different groups of 5 books, in 95,040 different sequences.

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because of gravity. i think

30 ways.

Alternate them.

Alternate them.

The answer to this one is 24. You can do this mathematically by 4*3*2*1.

There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520

Yes. They are real.

There are 5! (that is, 120) distinct ways to arrange five items. Only 1 of them will have the books in alphabetical order by title. So the probability that it happens by random is 1/120.

120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer

The answer would be 7! or (7*6*5*4*3*2*1)=5040

Choose 3 then 2 then 1; 3*2*1 = 6 ways.