it depends on the shelf of course
There are 8 ways to choose the first book There are 7 ways to choose the second book - 8 x 7 = 56 ways to select two books There are 6 ways to choose the third book - 8 x 7 x 6 = 336 way to select three books There are 5 ways to choose the fourth book - 8 x 7 x 6 x 5 = 1,680 ways to select four books.
you can arrange 8 pictures 28 different ways
Theorem: A number of permutation (the possible arrangements) of n distinct objects is n!Answer: There are 5! = 5 x 4 x 3 x 2 x 1 = 120 ways in which the five cereal boxes can be arranged in a shelf.
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30 ways.
To arrange 3 algebra books and 3 geometry books on a shelf so that no two books of the same type are next to each other, you can use the concept of permutations. There are 3! ways to arrange the algebra books and 3! ways to arrange the geometry books. This gives a total of 3! * 3! = 36 ways to arrange the books on the shelf such that no two books of the same type are next to each other.
Choose 3 then 2 then 1; 3*2*1 = 6 ways.
The answer would be 7! or (7*6*5*4*3*2*1)=5040
5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
Yes. They are real.
10!
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
Ill skip the factorials and just give you what the calculator does in the end. 8*7*6*5*4*3= 20,160