it depends on the shelf of course
There are 8 ways to choose the first book There are 7 ways to choose the second book - 8 x 7 = 56 ways to select two books There are 6 ways to choose the third book - 8 x 7 x 6 = 336 way to select three books There are 5 ways to choose the fourth book - 8 x 7 x 6 x 5 = 1,680 ways to select four books.
you can arrange 8 pictures 28 different ways
Theorem: A number of permutation (the possible arrangements) of n distinct objects is n!Answer: There are 5! = 5 x 4 x 3 x 2 x 1 = 120 ways in which the five cereal boxes can be arranged in a shelf.
6
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30 ways.
Choose 3 then 2 then 1; 3*2*1 = 6 ways.
The answer would be 7! or (7*6*5*4*3*2*1)=5040
5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
Yes. They are real.
10!
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
Ill skip the factorials and just give you what the calculator does in the end. 8*7*6*5*4*3= 20,160
it depends on the shelf of course