it is made by adding the outer digits as all the outer digits are 1. what your suppose to do is add the outer digits and you will get your pascals triangle. for example,, if there is 1 on both the sides then you add 1+1=2 so in the same way just keep adding and their you will have your pascals triangle.
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how are the odd numbers arranged Pascal's Triangle?
If going line by line, it is simply addition. Otherwise, it is combinatorials.
To find the values in row 135 of Pascal's Triangle, we use the formula C(n, k) = n! / (k! * (n-k)!), where n is the row number and k is the position in the row. In row 135, the values would be calculated as C(135, 0), C(135, 1), C(135, 2), ..., C(135, 135). These values would be 1, 135, 9030, 496005, and so on, following the pattern of Pascal's Triangle.
You can find the coefficients of an expanded binomial using the numbers in Pascal's triangle. 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 1 6 15 20 15 6 1 1 7 21 35 35 21 7 1 These are a few rows of Pascals triangle. Now let's look at a few binomials, expanded to the second and third powers. (a+b)2=a2 +2(ab) + b2 notice the coefficients are the numbers in the second row of the triangle above. (a+b)3= a3+3(a2b)+3(ab2)+b3 and once again note that the coefficients are the numberin the third line of Pascal's triangle. The first line, by the way, which is 1,1 is the coefficient of (a+b)1 This will work for any power of the binomial. There are generalized form for non-integer powers.
The terms in row 22 are 22Cr where r = 0, 1, 2, ..., 22. 22Cr = 22!/[r!*(22-r)!] where r! = r*(r-1)*...*3*2*1 and 0! = 1