1, 135, 135*134/(2*1), 135*134*133/(3*2*1) etc.
Wiki User
∙ 2010-06-22 14:04:55it is made by adding the outer digits as all the outer digits are 1. what your suppose to do is add the outer digits and you will get your pascals triangle. for example,, if there is 1 on both the sides then you add 1+1=2 so in the same way just keep adding and their you will have your pascals triangle. description by- anmol chawla of pathways world school
The terms in row 22 are 22Cr where r = 0, 1, 2, ..., 22. 22Cr = 22!/[r!*(22-r)!] where r! = r*(r-1)*...*3*2*1 and 0! = 1
You can find the coefficients of an expanded binomial using the numbers in Pascal's triangle. 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 1 6 15 20 15 6 1 1 7 21 35 35 21 7 1 These are a few rows of Pascals triangle. Now let's look at a few binomials, expanded to the second and third powers. (a+b)2=a2 +2(ab) + b2 notice the coefficients are the numbers in the second row of the triangle above. (a+b)3= a3+3(a2b)+3(ab2)+b3 and once again note that the coefficients are the numberin the third line of Pascal's triangle. The first line, by the way, which is 1,1 is the coefficient of (a+b)1 This will work for any power of the binomial. There are generalized form for non-integer powers.
The answer is 135. 15 times 9 equals 135 27 times 5 equals 135
right angled triangle
1,4,6,4,1
The sum of the 20th row in Pascal's triangle is 1048576.
the sum is 65,528
depends. If you start Pascals triangle with (1) or (1,1). The fifth row with then either be (1,4,6,4,1) or (1,5,10,10,5,1). The sums of which are respectively 16 and 32.
28354132 is the correct answer, I believe.
The sum is 24 = 16
1 5 10 10 5 1
If the top row of Pascal's triangle is "1 1", then the nth row of Pascals triangle consists of the coefficients of x in the expansion of (1 + x)n.
1, 9, 36, 84, 126, 126, 84, 36, 9, 1
The Fifth row of Pascal's triangle has 1,4,6,4,1. The sum is 16. Formula 2n-1 where n=5 Therefore 2n-1=25-1= 24 = 16.
Pascal's triangle
Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.