there is 0% probability, unless you are some super nerd, and calculate the chance of it splitting the six and you getting two threes in one roll :p
The probability of getting an even number on at least one of the 3 rolls is 7/8.
3_18 3_18
1/12 possibilty.
The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5
well its all 50% no matter what
It is 0.8217
The probability of getting an even number on at least one of the 3 rolls is 7/8.
If you rolled a die 120 times, the probability of getting a 6 is one in six. It does not matter how many times you roll the die - the probability is still one in six - except that the long term mean will approach the theoretical value of 0.166... as the number of trials increases.
Since the die is rolled (or even rooled) only 5 times, the answer is that the probability is 0.
It is approx 0.99989, that is, a near certainty.
Yes, it is possible.
The probability of a one being rolled in a fair die is 1 in 6, or 0.1666... . The probability of a one not being rolled is 5 in 6, or 0.8333... . The probability, then, of exactly one one being rolled in nine rolls is 1 in 6 times 5 in 6 to the 8th power, or about 0.0388.
It is 0.722... recurring.
The probability is 0.6187, approx.
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
The answer depends on how many times it is rolled.
15