It is 1 - 0.3120 = 0.6880, approx.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
if a die is rolled.What is the probibil ty that an even number divisible by 3 appears
When a tetrahedral die is rolled, it will rest with three faces upwards. If the die is numberd from 1 to 4. therefore the sum of the upward facing numbers on 1 die is at least 6 and so for two dice, the minimum is 12. That being the case, the probability is 0.
well, it will have 6 times of the greater chance.
An impossible event, with probability 0.
It is 0.722... recurring.
The probability is 0.6187, approx.
It is 0.9459
The probability that 14 is rolled at least once is 1 - 5.5*10-32 which, for all intents and purposes, can be treated as 1.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
The chance of any 1 number appearing in a die roll 3 times in a row is: 1/6 * 1/6 * 1/6 which is 1/216 = .00463
It is 0.1962
The answer depends on how many rolls. If there were n rolls, then the probability is n*(1/6)*(5/6)n-1/[1 - (5/6)n]
The probability is 1 and you do not need Matlab to get that answer - only a little bit of thought.
3/16 Michigan Virtual says it is 11/12
Probability(at least 1 six) = 1 - probability(no sixes) = 1 - 5/6 x 5/6 x 5/6 = 1 - 125/216 = 91/216 ≈ 0.421 = 42.1%
The probability is 1. At any point in time it is raining somewhere on earth.