question with options, you will lose of the credit for that question. Just like the similar multiple-choice penalty on most standardized tests, this rule is necessary to prevent random guessing.
With five choices, your chance of getting the question wrong is 80% when guessing, and every wrong answer costs you 1/4 of a point. In this case, leave it blank with no penalty. Guessing becomes a much better gamble if you can eliminate even one obviously incorrect response. If you can narrow the choices down to three possibilities by eliminating obvious wrong answers
The answer depends on the number of choices available for each question.
Well they are independent events so it is the probability of getting a correct answer multiplied by the probability of getting a correct answer on the second question. Short Answer: 1/5 times 1/5=1/25
If there are 4 choices and you randomly choose one, you have a 25% chance that it will be correct, with 75% that it will be wrong. However, if there is one answer that you know is not correct, you can eliminate that one. Then if you choose from the remaining three, you will have increased your chances of getting it right to 33%. That doesn't sound like a whole lot, but it really would help you.
The probability of correct true & false question is 1/2 and the probability correct multiple choice (four answer) question is 1/4. We want the probability of correct, correct, and correct. Therefore the probability all 3 questions correct is 1/2 * 1/2 * 1/4 = 1/16.
The probability of getting at least 1 answer correct = 1 - Probability of getting all answers correct.So in your case it for be P(at least 1 answer correct) = 1 - 1/256where 256 is your sample space, |S| = 2^8.
The answer depends on the number of choices available for each question.
Well they are independent events so it is the probability of getting a correct answer multiplied by the probability of getting a correct answer on the second question. Short Answer: 1/5 times 1/5=1/25
If you sent an incorrect question, you can try asking again. You have a better chance of getting a correct answer if the question is correct.
The probability of getting both answers correct is one chance in nine (0.1111+). There are three possible answers for each question, so there is a 1/3 chance of getting the correct answer to one question. To get the correct answer for both questions, the chances are 1/3 x 1/3 or 1/9.
That depends on how many questions there are, how many choices are listed for each question, and whether any obviously-stupid answers are included among the choices. If any of those factors changes, then the probability changes. One thing we can guarantee, however, even without knowing any of these factors: If you have studied the subject and know the material, then your probability of getting correct answers increases dramatically.
If there are 4 choices and you randomly choose one, you have a 25% chance that it will be correct, with 75% that it will be wrong. However, if there is one answer that you know is not correct, you can eliminate that one. Then if you choose from the remaining three, you will have increased your chances of getting it right to 33%. That doesn't sound like a whole lot, but it really would help you.
There is not enough information to answer the question sensibly. Is it implied that out of 200 students not one knew the answer to any one of the seven questions? And that all pupils had to make random choices for each question? Is that at all credible?
60
Getting is the correct spelling.
It is 0.0033
There is no best letter to choose; the test makers are aware of people trying to guess, so they purposely make it difficult to do so. Any guess is a guess and only gives you a 25% or 20% chance of getting the question correct (depending on if there are four or ive choices).
The probability of getting the first answer correct is 1/2 The probability of getting the first two correct is 1/2 * 1/2 = 1/(22) The probability of getting all 9 correct is 1/(29) = 1/512 which is just under 0.2%