In general, the probability that any child will be a girl is approximately 1 in 2. It is like flipping a coin. There is a 50-50 chance for a specific outcome each time. It would be less likely that a woman would have three sons than that she have two sons and one daughter, but each individual outcome is a 50-50 chance. If this is a brain teaser, since we are given that the woman has given birth to two sons, it could imply that any other children she has are daughters, in which case the probability is 100% - if we know that she has other children.
it one out 8 1/8 bc first child 1/2 second child 1/2 third child 1/2 1/2 x 1/2 x 1/2 = 1/8
0.25 binomial distribution, where p=0.5, q=0.5, x=3, n=4 4!/(3!*1!)*0.530.51 = 0.25 Also can be solved by identifying each event possible and related probability. There are 4 ways this can occur (first child is a girl, second child is a girl, third child is a girl and fourth child is a girl) and there is a 0.54 chance of each of these events occurring. Prob= 4 *0.0625 = 0.25
One in 336
Aprox. 0.018%There are 4 queens in a regular deck of 52 cards.The probability of drawing a queen on the first draw is: P(Q1) = 4/52.The probability of drawing a queen on the second draw given that the first card wasa queen is: P(Q2│Q1) = 3/51.The probability of drawing a queen on the third draw given that the first two cardswere queens is: P(Q3│(Q2UQ1)) = 2/50.The probability of drawing 3 queens on the first 3 cards drawn from a deck of cardsis: P(Q1UQ2UQ3) = (4/52)∙(3/51)∙(2/50) = 1.80995... x 10-4 ≈ 0.00018 ≈ 0.018%
the probability of a house will be burglarized is = 5% which is = .05 the probability of a house will NOT be burglarized is = (1 - .05) the probability of a second house will NOT be burglarized is = (1-.05)*(1-.05)= (1-.05)^2 the probability of a third house will NOT be burglarized is= (1-.05)*(1-.05)(1-.05)= (1-.05)^3 so, the probability of NONE = (1-.05)^10 = .598736939 = .5987
There are no relationship between this 3 events, the probability to give birth to a girl can not be deduce from previous birth given by a women. So the probability that the third child will be a girl is the same for this woman as for any other woman, no matter what happened before. It's like rolling a dice, if one gets an ace and an ace, it does not change the chance to get another ace for the third roll, or a 2, or a 3,.... All the roll results are independent if the dice is not loaded
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that they are independent events then, the probability that the third child is a girl is the same as the probability that any birth is a girl - which is 0.48 across the world.
One half. A mother always contributes an "X" chromosome to the offspring. The father's semen contains a mix of "X" and "Y" sperm, and it is mostly a matter of chance as to which one fertilizes the egg.
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
Seth was the third son of Adam and Eve. His birth was mentioned in Genesis 4:25. The couple would have rejoiced in the child's birth anyway. But they particularly rejoiced over God having given* them a son to replace the hardworking, kindly Abel. The younger Abel was killed by the couple's older son, Cain.*The name 'Seth' resembles the Hebrew for 'has given'.
He was not he was the third out of ten two died at birth
"one third" is not an event and so cannot have complement nor a probability.
How many brothers or sisters do i have?
Wrestling sites are reporting that see gave birth on August 24th, Vince's birthday.
complications in childbirth. She died after giving birth to the third child to survive Lucy
Yes, a baby girl called Petal
same probable as the first child having it. By doing the punnet square, they are both recessive for the disease. There is a 25% chance that the child will get the disease.