hypergeometric distribution f(k;N,n,m) = f(1;51,3,1)
or binominal distribution f(k;n,p) = f(1;1,3/51) would result in same probability
"Playing cards" are chosen at random.
The probability of drawing the first ace is 4 in 52. The probability of getting the second ace is 3 in 51. The probability of getting the third ace is 2 in 50. The probability, then, of drawing three aces is (4 in 52) times (3 in 51) times (2 in 50), which is 24 in 132600, or 1 in 5525, or about 0.0001810
If you answer randomly, 1 in 8.
There are infinitely many numbers and so the probability of the second event is 0. As a result the overall probability is 0.
The answer depends on how many cards are drawn.
"Playing cards" are chosen at random.
The probability of getting an 8 on a standard six-sided die is zero.
The probability of getting two pairs in a standard deck of playing cards is higher than the probability of getting three of a kind.
If the events can be considered independent then the probability is (0.7)4 = 0.24 approx.
The probability of drawing the first ace is 4 in 52. The probability of getting the second ace is 3 in 51. The probability of getting the third ace is 2 in 50. The probability, then, of drawing three aces is (4 in 52) times (3 in 51) times (2 in 50), which is 24 in 132600, or 1 in 5525, or about 0.0001810
If you answer randomly, 1 in 8.
The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.
There are infinitely many numbers and so the probability of the second event is 0. As a result the overall probability is 0.
The answer depends on how many cards are drawn.
hypergeometric distribution f(k;N,n,m) = f(3;52,4,3)
If you pick enough cards, without replacement, the probability is 1. The probability for a single random draw is 1/26.
The probability of getting a positive answer from a magic 8 ball depends on the number of positive responses it contains. A standard magic 8 ball typically has 20 possible answers, of which 10 can be considered positive (e.g., "Yes," "Definitely," "Ask again later"). This gives a rough probability of 50% for receiving a positive answer, assuming the responses are evenly distributed and randomly selected.