There is only one median in a set of values. If it is an odd amount of values, the median is the middle number. If there is an even amount of numbers, the median is the value halfway between the two middle numbers. So, in 1, 2, 3; the median is 2. In 1, 2, 3, 4; the median is 2.5, as that is halfway between 2 and 3.
in general,mean is more stable than median but in the case of extreme values it is better to consider median a stable measure than mean.
median
Yes. If the lower values tend to be farther below the median than the highest values are above the median, the mean is smaller than the median. why are write wrong
Either one can be larger (or smaller) than the other.
When a distribution is skewed to the right, the mean is greater than median.
No and a single number cannot have a median either you need a series (at least two) to have a median.
in general,mean is more stable than median but in the case of extreme values it is better to consider median a stable measure than mean.
When the distribution has outliers. They will skew the mean but will not affect the median.
Yes. If the predominant data are higher than the median, the mean average will be higher than the median average. For example, the median average of the numbers one through ten is five. The mean average is five and one-half.
No.There is only 1 middle value.If there are an odd number of elements in the data set, the median is the middle one;Otherwise there are an even number of elements in the data set and the median is the mean average of the middle two (add them together and divide by 2).The median value can occur more than once in the data set, eg in {2, 5, 5, 5, 6, 7} the median is 5 ((5 + 5)/2 = 5) with a frequency of 3, but it is still only one value.
Median is the middle number in a group of numbers. If there more than one middle number, the median is either shown as average of the two numbers in the middle or shown as both the numbers. The median in 23 24 26 29 is 25 or {24;26}.
If you have an even set of data then there are two middle numbers or medians. Average those two and create a median. Example: 2,3,4,7,9,10 4 and 7 are in the middle. (4+7)/2=5.5 5.5 is the median even though it is not one of the numbers in the data set.
the intersection of less and more than ogive gives us the median of the following data.. but the median is not accurate as we draw the free hand cumulative graph..
median
The median can be found out by drawing a perpendicular to the x-axis from the intersection point of both the ogives
Yes, it is.
Yes. If the lower values tend to be farther below the median than the highest values are above the median, the mean is smaller than the median. why are write wrong