It is 1/7 if a ball is selected at random.
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
zero
2
3 out of 13 or 3/13
If the balls are selected at random, then the probability is 12/95.
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
zero
3/12*3/11 = 9/132, or 6.818%.
2
3 out of 13 or 3/13
If the balls are selected at random, then the probability is 12/95.
The probability is 3/7 * 2/6 * 1/5 = 1/35.
There are 18 Green balls and 12 Blue balls. You have to pick 2 blue balls, so the green balls don't matter. You can pick 1 blue ball on 12 ways. The second ball you can pick on 11 ways (because there are 11 balls left). 12 * 11 = 132. So you can pick it on 132 ways. ;)
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
3c2+2c2+3c1 2c1 --------------- 7c2. I have done it this way. 3C2 means that the both balls would be green 2C2 both would be red and 3C1 and 2C1 because both the balls can be red and green.
The probability is (6/14)*(5/13) = 30/182 = 0.1648 approx.
ans : 3720