For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times
I'm assuming you're looking for the probability that you roll either a one or six at least once. So the problem can be rewritten as: 1 - probability of rolling 60 times and never getting ones or sixes = 1 - (2/3)^60
If p is the probability that an event will happen once, then the probability that it will happen just twice is p2. The probability it will happen 3 times is p3. The probability it will happen at least once ( ie once or twice or three times ore more times is p + p2 + p3 + ... = p(1-p). For "or" you add probabilities, for "and" you multiply probabilities.
The probability is 0.998
The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%
The probability is 5/16.
It is 0.3125
The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.
It is 1/32 = 0.03125
Since each event is independent, the probability remains at 0.5.
It is 60/100 = 0.6
one out of 5 or 2 out of 10
It is 1/8 = 0.125
Because a coin is two-sided, 50/50 is always the probability. Unless your coin lands on the grass (on the lawn), then it will probably land on its edge.
3 out of 6