answersLogoWhite

0

6 permute 6

=720 ways :))

User Avatar

Wiki User

13y ago

Still curious? Ask our experts.

Chat with our AI personalities

ReneRene
Change my mind. I dare you.
Chat with Rene
JudyJudy
Simplicity is my specialty.
Chat with Judy
ViviVivi
Your ride-or-die bestie who's seen you through every high and low.
Chat with Vivi

Add your answer:

Earn +20 pts
Q: In how many different orders can 6 runners finish a race?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Statistics

A supplier must fill four large orders How many different ways can those orders be arranged?

i am doing this same question for a stats midterm and i am thinking that it is chronological, numerical, aplhabetical (order of items) and by date


How many ways can 9 runners be arranged on a 4 person relay team?

9x8x7x6 = 3024.


What is a one-to-many relationship?

It is a term from computer databases. A relational database can have a one-to-many relationship in its data. For example, if you have a customer order database, one table will contain customer names and another will contain their orders. Each customer will only be listed once, but each customer can make many orders. So one customer can be related to many orders. Incorporating that into a database requires the creation of a one to many relationship.


How many ways can you arrange 4 different cubes?

The cubes can be arranged in a line in 24 orders, and each cube can be arranged in 24 orientations so the answer is 24*24 = 576 ways. Of course, the question does not require then to be in a line so there are really infinitely many ways: for example one cube in your house, one in your garden, one in my house and one in my garden. Move one of them a bit and that's a different arrangement.


What is the probability of getting two heads one tail when you spin 3 coins?

First work out the probability of the first two coins being heads and then the last being tails. This is 1/2 x 1/2 x 1/2 which is 1/8 The next step is to find out how many different orders the coins can come in. In this case there are 3 possible orders (HHT, HTH, and THH). Multiply this by the above probability and you get 3/8. Therefore the probability of getting two heads and one tail is 3/8