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In how many ways can the letters of the word permutations be arranged if there are always 4 letters between p and s?
Wiki User
∙ 11y ago
Here P and S are fixed, so 10 letters are left, out of which 2 are T's
So, 10 letters out of which 2 are T's can be arranged in 10!/2! = 1814400 ways
Now letters P and S can be arranged so that there are 4 letters between them, which can be done in 2*7 = 14 ways
Required no. of ways = 1814400 * 14 = 25401600
Wiki User
∙ 11y ago
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How many ways can 9 books be arranged on a shelf so that 5 of the books are always together?
You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations. Permutations of five objects is 5!, five gives 5!, so the total permutations are: 5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations
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How many ways can 9 books be arranged on a shelf so that 5 of the books are always together?
You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations. Permutations of five objects is 5!, five gives 5!, so the total permutations are: 5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations
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the word leading contains 7 different letters,when the vowels eai r always together they can be supposed to form 1 letter then we have to arrange ldng (eai) now,5 letters can be arranged in 5!ways=120 ways the vowels (eai)can be arranged in 3! ways=6ways required no of ways =120*6=720 by deepika.R(RVS CET)
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