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1/2*1/2*1/2*1/2+1/2*1/2*1/2*1/2+1/2*1/2*1/2*1/2+1/2*1/2*1/2*1/2+1/2*1/2*1/2*1/2+1/2*1/2*1/2*1/2+1/2*1/2*1/2*1/2+1/2*1/2*1/2*1/2= 1/2
Variance = sigma((value - mean)2) / (# values - 1) Mean = (0+1+1+2)/4 = 1 Variance = ((0-1)2+(1-1)2+(1-1)2+(2-1)2)/(4-1) Variance = (1+0+0+1)/3 Variance = 2/3 Variance ~ 0.667
(1/2)*(1/2)*(1/2)*(1/2)*(1/2)*(1/2) = 1/26 = 1/64
The probability of getting a combination of three heads and one tail regardless of theorder when you toss a coin four times is:P(THHH or HTHH or HHTH or HHHT) = P(THHH) + P(HTHH) + P(HHTH) + P(HHHT) =1/2(1/2)(1/2)(1/2) + 1/2(1/2)(1/2)(1/2) +1/2(1/2)(1/2)(1/2) + 1/2(1/2)(1/2)(1/2) = 4/16 = 1/4
The answer is 1 in 2^10 or 1 in 1024 or approximately 0.098%. While there is a 50% chance of getting a heads or tails in a FAIR coin toss during each toss, there is a very low likelihood of getting 10 in row as follows: 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 = 1 / 1024 = approximately 0.098%.