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What is the probability of not drawing a green marble?
To calculate the probability of not drawing a green marble, first determine the total number of marbles and the number of green marbles. The probability of not drawing a green marble is then given by the ratio of the number of non-green marbles to the total number of marbles. This can be expressed as: [ P(\text{not green}) = \frac{\text{Number of non-green marbles}}{\text{Total number of marbles}}. ] Without specific numbers, the exact probability cannot be computed.
Is the probability that a blue marble will NOT be selected from a bag containing 9 red marbles 6 blue marbles 7 green marbles and 11 yellow marbles if one is selected randomly?
To find the probability that a blue marble will NOT be selected, first calculate the total number of marbles: 9 red + 6 blue + 7 green + 11 yellow = 33 marbles. The number of non-blue marbles is 9 red + 7 green + 11 yellow = 27 marbles. Therefore, the probability of NOT selecting a blue marble is 27/33, which simplifies to 9/11.
What is the experimental probability of choosing a green marble if there are 7 red 9 yellow 14 green and 10 purple?
To find the experimental probability of choosing a green marble, first calculate the total number of marbles: 7 red + 9 yellow + 14 green + 10 purple = 40 marbles. The probability of choosing a green marble is the number of green marbles divided by the total number of marbles, which is 14 green / 40 total = 0.35. Thus, the experimental probability of choosing a green marble is 0.35, or 35%.
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
How do you shatter marbles?
Wear protective eye gear !first heat marbles in fire until very hot then scoop marbles out with spoon or tongs so you don't burn yourself then drop hot marble into cold water
A bag contains 6 purple marbles and 7 white marbles Two marbles are drawn at random One marble is drawn and not replaced Then a second marble is drawn What is the probability that the first marble?
There are 13 marbles in total. The order is specified.P(1st is white and the 2ndis purple) = (7/13)(6/12) = (7/13)(1/2) = 7/26.
If A bag contains 3 red marbles and 5 purple marbles One marble is drawn at random and not replaced Then a second marble is drawn at random What is the probability that the first marble is purple and?
3/5
A bag contains five green marbles and four red marbles what is the odds of in favor picking a green marble on the first selection?
There is a one in 2 chance of getting a green marble.
In a bag there are 4 red marbles 5 white marbles and 6 blue marbles once a marble is selected it is not replaced what are the odds of pulling a red marble than a white marble?
The odds of pulling a red marble on the first try is 4/15 or about .27 and the probability of drawing a white marble the second time if a the first is a red marble is 5/14 or about .36. the odds of both happening is the product of the probabilities of the other events, or 2/21.
If you have 50 black marbles and 50 white marbles in a bag at most how many times would you have to draw out a marble to get two the same colour?
The maximum number of marbles you have to draw is three. 1) Draw a marble. It is either white or black. 2) Draw a second marble. If it is the same colour as the first marble, we are done after two draws. 3) Otherwise, the drawn marbles have different colours. Draw a third marble. No matter what you draw next, you must have two marbles of the same colour.
How do you play a game of marbles with jokers included in the rules?
To play a game of marbles with jokers included in the rules, each player starts with a set number of marbles and a joker marble. The joker marble can be used strategically to gain an advantage during the game. Players take turns shooting their marbles towards a target, trying to knock out their opponent's marbles. The joker marble can be used to hit other marbles or to protect your own marbles from being knocked out. The player who knocks out all of their opponent's marbles first wins the game.
When a marble hits a row of marbles why does only one marble fly of?
When a marble hits a row of marbles, only one marble flies off due to the conservation of momentum. The kinetic energy from the first marble is transferred to the second marble at the end of the row, causing it to move while the others remain stationary. It's a chain reaction that propagates the energy through the row.
If a bag contains 3 green marbles 5 blue marbles and 2 yellow marbles find the probability that the marble is blue?
Assuming that you're only taking out one marble, then:Your sample space --> 3 + 5 + 2 = 10The probability of getting a blue marble on the first draw is 3/10 or 0.3
Is the probability that a blue marble will NOT be selected from a bag containing 9 red marbles 6 blue marbles 7 green marbles and 11 yellow marbles if one is selected randomly?
To find the probability that a blue marble will NOT be selected, first calculate the total number of marbles: 9 red + 6 blue + 7 green + 11 yellow = 33 marbles. The number of non-blue marbles is 9 red + 7 green + 11 yellow = 27 marbles. Therefore, the probability of NOT selecting a blue marble is 27/33, which simplifies to 9/11.
A bag that has 7 greens marbles 3 blue marbles and 12 white marbles what is the probability of selecting a white marble on each of the three tries if the marble is placed back after each pick?
12 white marbles from (7+3+12) = 22 marblesChance of a white marble on first pick = 12/22 = 6/11.Chance of a white marble on second and third picks are the same, as the marble is replaced.So, the chance of a white marble three times is 6/11 * 6/11 * 6/11 = 216/1331 = approximately 16.23%
What is the probability of drawing a white marble then a red marble if there are 3 red marbles and 2 white marbles?
5 marbles. 3 red marbles, 2 white marbles.The probability of drawing a white marble is P(W) = 2/5 = 0.40If the white marble is not returned to the rest of the marbles (no substitution), theprobability that the second marble drawn is a red one is P(R) = 3/4 = 0.75.The probability that the event of drawing first a white marble and without substitutionthe second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/4) = 6/20 = 3/10 = 0.30 = 30.0%.If the process of drawing the marbles is with substitution, the probability of thesecond draw turning a red marble is P(R) = 3/5 = 0.60 = 60.0%The probability that the event of first drawing a white marble and after returning themarble back to the original group of marbles (with substitution) the second draw turns a red marble is P(1stW,2ndR) = (2/5)∙(3/5) = 6/25 = 0.24 = 24.0%.
A bag contains 6 red marbles 9 blue marbles and 5 green marbles You withdraw one marble replace it and withdraw another marble What is the probability that you do not draw two green marbles 25 denomo?
To calculate the probability of not drawing two green marbles, we first find the probability of drawing a green marble on the first draw, which is 5/20 since there are 5 green marbles out of a total of 20 marbles. The probability of not drawing a green marble on the first draw is 1 - 5/20 = 15/20. Since the marbles are replaced, the probability of not drawing a green marble on the second draw is also 15/20. Therefore, the probability of not drawing two green marbles is (15/20) * (15/20) = 225/400 = 9/16 or 56.25%.
