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If the odd favoring an event are 10 to 1, then the probability of the event occurring is 0.9.

The odds in favor of an event are 10:1.

Find the probability that the event will occur.

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P(E)+P(E') = 1

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P(E)/P(E') = 10/1

So P(E) = 10P(E')

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Substitute for P(E) and solve for P(E'):

10P(E')+P(E') = 1

11P(E') = 1

P(E') = 1/11

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Therefore P(E) = 10/11

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Q: The odds in favor of an event are 10 to1 ratio Find the probability that the event will occur?
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Continue Learning about Statistics

The ratio of the probability that an event will occur compared with the probability of its not occurring?

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The ratio of the probability that an event will occur compared with the probability of its not occurring?

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