23/48
s=sample standard deviation s=square root (Sum(x-(xbar))2 /(n-1) Computing formula (so you don't have to find the mean and the distance from the mean over and over): square root(Sxx /(n-1)) Sxx= Sum(x2) - ((Sum(x))2/n)
There are 36 permutations of two dice. Of these, 10 sum to less than six; 1+1, 1+2, 1+3, 1+4, 2+1, 2+2, 2+3, 3+1, 3+2, and 4+1. The probability, then, of rolling a sum less than six is 10 in 36, or 5 in 18, or about 0.2778.
Sum, or summation, is just addition. For example, the sum of 1 and 2 is 1 + 2 = 3. The term "sum" is generally used for large sets or series. For example, the sum of the first 100 natural numbers is 1 + 2 + 3 + ... + 100 = 495. Sum is the total of 2 or more numbers as determined by the math process. Mathematically it means the answer to an addition problem.
It is 1 - Pr(rolling a sum of 5 with two dice) = 1 - Pr(1+4 or 2+3 or 3+2 or 4+1) = 1 - 4/36 = 8/9
(1) That the probabilities lie between 0 and 1. (2) The sum of all probabilities of the distribution sum up to 1.
The numbers 32 and 1 (32 x 1 = 32) sum to 33. The numbers 4 and 8 (4 x 8 = 32) sum to 12 The numbers 2 and 16 (2 x 16 = 32) sum to 18. There are no other factors which are integers, so 32 and 1 is the answer.
1/2 minus 5/32 is 11/32
5/32 + 1/2 = 5/32 + 16/32 = 21/32
The sum of those fractions is 9 over 10 or 9/10.
1.5 or 1 + 1 over 2
The sum of 1/8 and 3/8 is 1/2
2 over 8
1 over 2 or 1/2
Factors of 20 are 1, 2, 4, 5, 10 and 20. And their sum is 1 + 2 + 4 + 5 + 10 + 20 = 32.
I am going to assume you are asking for the sum of 87 and 1/2 of 64. First, you solve for 1/2 of 64: 1/2 x 64 = 32. Next, add 87 and 32: 87 + 32 = 119.
The sum of a geometric sequence is a(1-rn)/(1-r) In this case, a = 8, r = -2 and n=15 So the sum is 8(1-(-2)15)/(1+2) =8(1+32768)/3 =87,384 So the sum of the first 15 terms of the sequence 8, -16, 32, -64.... is 87,384.
No. The proper divisors of 32 are 1, 2, 4, 8, and 16. Their sum, 1 + 2 + 4 + 8 + 16 = 31, which is less than 32, so it is not an abundant number.