lets call the one number X and the other Y so y equals 3X
so 3X plus X equals 84
so 4X equals 84
we divide by 4 so x equals 21
so y equals 21 times 3 equals 63
so the two numbers are 63 and 21
The two numbers that solve this problem are 5 and 15. The sum of 5 and 15 is equal to 20, and 15 is indeed 3 times 5.
Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.
1,2,3,4 1+2+3+4=10 4 times 3 times 2 times 1 =24 24 counting numbers
The mode is the number that most often occurs. As both 19 and 22 occur three times, then there is no mode.
The numbers are 21 and 63.
One number is 63 and the other is 21.
Since one number is 3 times the other, I'd divide 84 by 4 and get 21. This is the lower number so the other must be 63.
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
The greater of two numbers is 7 more than the lesser Three times the greater number is 5 more than 4 times the lesser number Find the numbers?
The mean times three will be the total of all three numbers. Multiply the mean times three and subtract the sum of the two numbers from that total.
Their sum is three times the middle number.
Each number is three times the previous number.
12 and 28
number is 14 and the other is 56